添加详细信息链接结构

Question

我写了这个代码：（以上结构和下方的功能）

list * add_student(slist * students, char * name, int id) { 
    slist * temp, * adder; 

    if (!(adder = (slist *) 
     malloc(sizeof(slist)))) exit(1); 

    student * data; 

    if (!(data = (student *) 
     malloc(sizeof(student)))) exit(1); 

    data - > name = name; 
    data - > id = id; 
    data - > courses = NULL; 
    adder - > info = data; 
    adder - > next = NULL; 

    if (!students) { 
     return adder; 
    } 

    for (temp = students; temp - > next; temp = temp - > next); 
    temp - > next = adder; 
    return students; 
} 

的结构是：

typedef struct course { 
    char *title; 
    int number; 
    struct slist *students; 
} course; 

typedef struct slist { 
    student  *info; 
    struct slist *next; 
} slist; 

typedef struct clist { 
    course  *info; 
    struct clist *next; 
} clist; 

第一个功能是应该的学生加入到学生名单。 它增加了学生，但如果我试图把另一名学生，名称正在替换第一个名称（只有名称不是数字）。

我无法找到代码中的错误生病真的很感谢您的帮助。

谢谢。

Answer 1

分配内存名称和名称参数复制：

list * add_student(slist * students, char * name, int id) { 
    slist * temp, * adder; 
    if (!(adder = (slist *) malloc(sizeof(slist)))) exit(1); 
    student * data; 
    if (!(data = (student *) malloc(sizeof(student)))) exit(1); 
    if (!(data->name = (char *) malloc(sizeof(char) * (strlen(name)+1)))) exit(1); 
    strcpy(data->name, name); 
    data->id = id; 
    data->courses = NULL; 
    adder->info = data; 
    adder->next = NULL; 
    if (!students) { 
    return adder; 
    } 
    for (temp = students; temp - > next; temp = temp - > next); 
    temp - > next = adder; 
    return students; 
}