2014-11-05 79 views
0

我有一个列表视图,它有两种不同的布局类型。带有Viewholder的Android Listview返回重复条目

1:共享 2:不共享

简单。

我正在使用一个viewholder来处理回收,但由于某些原因,我仍然在列表视图中获取重复条目。

BIG NOTE:我不想根据项目在列表视图上的位置来更改布局,因此我不认为使用getItemViewType会有所帮助,那么我可能会错误。

我正在改变项目布局,取决于从数据库传回的布尔值。

下面是代码:

@Override 
public View getItemView(final StatusItem status, View convertView, ViewGroup parent) { 

    View view = convertView; 

    // we'll set up the ViewHolder 
    ViewHolder viewHolder; 

    shared = status.getShared(); 

    if (view == null) { 
     // If view is null 
     viewHolder = new ViewHolder(); 

     if (shared) { 
      // if the status is shared use this layout 
      view = mInflater.inflate(R.layout.status_list_view_item_shared, parent, false); 
      viewHolder.OUserName = (TextView) view.findViewById(R.id.OUserName); 
      viewHolder.OUserName.setText("@" + status.getOUN()); 

      viewHolder.sharedText= (TextView) view.findViewById(R.id.sharedText); 
      viewHolder.sharedText.setText(status.getSharedStatus()); 
     } else { 
      // if the status is not shared use this layout 
      view = mInflater.inflate(R.layout.status_list_view_item, parent, false); 
     } 

     mListViewReferences(view, status, viewHolder); 
     loadProfileImages(status, viewHolder); 
     view.setTag(viewHolder); 
    } else { 
     // we've just avoided calling findViewById() on resource everytime 
     viewHolder = (ViewHolder) view.getTag(); 
    } 

这里是我的viewHolder

private static class ViewHolder { 
    TextView statusUserName, timePosted, OUserName, sharedText, commentCounter, likeCounter, statusText; 
    ImageButton statusLike, statusComments, statusShare, statusMenu; 
    ImageView statusProfilePic; 
    LinearLayout likeCounterLayout, commentCounterLayout; 

} 

回答

2

试试这个兄弟或爵士?

@Override 
public View getItemView(final StatusItem status, View convertView, ViewGroup parent) { 

View view = convertView; 

// we'll set up the ViewHolder 
ViewHolder viewHolder; 

shared = status.getShared(); 

if (view == null) { 
    // If view is null 
    viewHolder = new ViewHolder(); 

    if (shared) { 
     // if the status is shared use this layout 
     view = mInflater.inflate(R.layout.status_list_view_item_shared, parent, false); 
     viewHolder.OUserName = (TextView) view.findViewById(R.id.OUserName); 
     viewHolder.OUserName.setText("@" + status.getOUN()); 

     viewHolder.sharedText= (TextView) view.findViewById(R.id.sharedText); 
     viewHolder.sharedText.setText(status.getSharedStatus()); 
    } else { 
     // if the status is not shared use this layout 
     view = mInflater.inflate(R.layout.status_list_view_item, parent, false); 
    }   
} else { 
    // we've just avoided calling findViewById() on resource everytime 
    viewHolder = (ViewHolder) view.getTag(); 
} 

mListViewReferences(view, status, viewHolder); 
loadProfileImages(status, viewHolder); 
view.setTag(viewHolder); 
} 

复制,粘贴和尝试..确保它们是你的视野之外为空,如果条件和你的getview内部方法

+0

笑哇,我简直不敢相信它是如此简单。我以前是这样做的,但具有不同的逻辑,所以我仍然得到重复的条目。猜猜我在整个过程中迷失了方向,忘记把它放回if/else语句之外。 IT是几小时或节目对你做的事情。非常感谢。 – user123859 2014-11-05 02:59:58

+0

大声笑..我可以做的是el el el,并且也要感谢你..以及你所说的“IT是什么时间或节目对你做什么”,这是非常真实的,这就是为什么你总是重新检查代码。 ...快乐的编码.. @ user123859 – Elltz 2014-11-05 03:02:18