安卓：垂直的ListView重叠的行

Question

如何在Android的1.6或2创建列表视图这样的（因为的renderScript，它只能在3或更高版本的，但我需要清单的工作在几乎所有的机器人）：

Answer 1

我在drawChild中使用了Camera.setTranslate(x, 0, z)，其中用于旋转虚拟化的x位置被改变，用于重叠的z被改变。然后有重叠的问题，因为最后一个项目在顶层，第一个在底层。所以，在onCreate()方法称为this.setChildrenDrawingOrderEnabled(true)和重写protected int getChildDrawingOrder (int childCount, int i) {}在那里我可以为中期，后期行更改订单。 这个想法是由雷纳德给出的，他在我的其他帖子中提出了关于几乎相同的东西here。

我getChildDrawingOrder（INT，INT）实施得到重叠的，我需要：

@Override 
protected int getChildDrawingOrder (int childCount, int i) { 
    int centerChild = 0; 
    //find center row 
    if ((childCount % 2) == 0) { //even childCount number 
     centerChild = childCount/2; // if childCount 8 (actualy 0 - 7), then 4 and 4-1 = 3 is in centre.  
     int otherCenterChild = centerChild - 1; 
     //Which more in center? 
     View child = this.getChildAt(centerChild); 
     final int top = child.getTop(); 
     final int bottom = child.getBottom(); 
     //if this row goes through center then this 
     final int absParentCenterY = getTop() + getHeight()/2; 
     //Log.i("even", i + " from " + (childCount - 1) + ", while centerChild = " + centerChild); 
     if ((top < absParentCenterY) && (bottom > absParentCenterY)) { 
      //this child is in center line, so it is last 
      //centerChild is in center, no need to change 
     } else { 
      centerChild = otherCenterChild; 
     } 
    } 
    else {//not even - done 
     centerChild = childCount/2; 
     //Log.i("not even", i + " from " + (childCount - 1) + ", while centerChild = " + centerChild); 
    } 

    int rez = i; 
    //find drawIndex by centerChild 
    if (i > centerChild) { 
     //below center 
     rez = (childCount - 1) - i + centerChild; 
    } else if (i == centerChild) { 
     //center row 
     //draw it last 
     rez = childCount - 1; 
    } else { 
     //above center - draw as always 
     // i < centerChild 
     rez = i; 
    } 
    //Log.i("return", "" + rez); 
    return rez; 

} 

我希望这篇文章将帮助别人在未来

截图实际上几乎是一样的，因为我在我的问题提到。我使用的α，所以重叠的项目是一点点透视：