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我已经在一台机器上写了相同的代码，它工作正常，但在其他机器相同的代码给错误意外的输入结束。为什么会这样呢，这让我疯狂。任何人都可以帮忙，请。这些是我工作的文件。意外的输入结束php jQuery
编辑：我正在做一个小型在线测试应用程序的学习目的。在测试开始时，出现第一个问题，点击下一步按钮时，url会变为应该出现的状态，但下一个问题不会出现，并且控制台中的错误表示输入的意外结束。由于我所有的括号都可以，所以我无法找到错误。请帮忙！！
TestStart.php
<?php
session_start();
if(isset($_SESSION['TestId']))
{
$TestId = $_SESSION['TestId'];
}
include('Config.php');
include('Reference.php');
$query = "select * from testquestions where testid='".$TestId."'";
$res = mysql_query($query);
if(mysql_num_rows($res) > 0)
{
$z = array();
while($fetch = mysql_fetch_array($res))
{
$z[]=$fetch['QId'];
}
$y = implode(",", $z);
$_SESSION['QIds']=$z;
}
else{
echo mysql_error();
}
?>
<body>
<div class="container">
<div class="row">
<div class="col-md-12" id="resultDiv">
<div class="col-md-12" id="qtext"></div>
<div class="col-md-12">
<div class="col-md-3">
<div class="col-md-12">
<input type="radio" id="optionA"name="options" value="A"><span id="optA"></span>
</div>
<div class="col-md-12">
<input type="radio" id="optionB" name="options" Value="B"><span id="optB"></span>
</div>
</div>
<div class="col-md-3">
<div class="col-md-12">
<input type="radio" id="optionC" name="options" value="C"><span id="optC"></span>
</div>
<div class="col-md-12">
<input type="radio" id="optionD" name="options" value="D"><span id="optD"></span>
</div>
</div>
</div>
<div id="nextbuttondiv"></div>
</div>
</div>
</div>
<script>
$(document).ready(function(){
<?php
if(isset($_GET['qno'])&&isset($_GET['qindex']))
{
$qno = $_GET['qno'];
$qindex = $_GET['qindex'];
}
else{
$qno = '1';
$qindex = '0';
}
?>
var qno = <?php echo $qno;?>;
var qindex = <?php echo $qindex;?>;
var qidsarrCm = '<?php echo $y;?>';
var arrQid = qidsarrCm.split(",");
var totalQuestions = arrQid.length;
$.ajax({
type : "post",
url : "GetQuestionForTest.php",
data : {
"quId" : arrQid[qindex]
},
dataType : "json",
success : function(data){
alert('xy');
console.log(data);
$.each(data, function(){
var qText = this.questiontext;
var optionA = this.OptionA;
var optionB = this.OptionB;
var optionC = this.OptionC;
var optionD = this.OptionD;
var nxtBtn = this.NextButton;
$('#qtext').text(qText);
$('#optA').text(optionA);
$('#optB').text(optionB);
$('#optC').text(optionC);
$('#optD').text(optionD);
$('#nextbuttondiv').html(nxtBtn);
});
},
error: function(data, statusCode, xhr){
alert(statusCode);
console.log(data);
console.log(xhr);
}
});
$('input[type=radio]').on('click',function(){
$('.nxtbtn').removeAttr('disabled');
});
$('body').on('click','.nxtbtn', function(){
$.ajax({
type : "post",
url : "SaveTestAnswers.php",
data : {
"qid" : arrQid[qindex],
"ansId" : $('input[name=options]:checked').val(),
"stuId" : <?php echo $_SESSION['CurrentUser'];?>,
"testId" : <?php echo $TestId;?>
},
dataType : "json",
success : function(data){
if(data.toString() == "true"){
qindex = qindex + 1;
qno = qno + 1;
if(qno > totalQuestions){
window.location.href="TestFinish.php";
}
else{
window.location.href="TestStart.php?qno="+qno+"&qindex="+qindex;
}
}
else{
alert(data + "Please resubmit the answer");
}
},
error : function(data, statusCode, xhr){
alert(statusCode);
console.log(data);
console.log(xhr);
}
});
});
});
</script>
</body>
GetQuestionForTest.php
<?php
$questionid = $_POST['quId'];
include('Config.php');
$query = "select * from questionstable where questionid = '".$questionid."'";
$result = mysql_query($query);
if(mysql_num_rows($result) > 0)
{
$someArray = [];
while($fetch = mysql_fetch_array($result))
{
array_push($someArray,[
'questiontext' => $fetch['questiontext'],
'OptionA' => $fetch['optionA'],
'OptionB' => $fetch['optionB'],
'OptionC' => $fetch['optionC'],
'OptionD' => $fetch['optionD'],
'NextButton' => '<button class="btn btn-success nxtbtn" disabled >Next</button>'
]);
}
$someJSON = json_encode($someArray);
echo $someJSON;
}
else{
echo mysql_error();
}
?>
SaveTestAnswers.php
<?php
$qid = $_POST['qid'];
$ansId = $_POST['ansId'];
$stuId = $_POST['stuId'];
$testId = $_POST['testId'];
include('Config.php');
$query = "insert into testattemptedanswers(StudentId,TestId,QuestionId,AnswerGiven) values('".$stuId."','".$testId."','".$qid."','".$ansId."')";
$res = mysql_query($query);
if($res){
echo 'true';
}
else{
echo 'false'.mysql_error();
}
?>
请告诉我们ü[R得到确切的错误。发布代码是不够的。 – Pushkar
考虑使用mysqli或pdo – madalinivascu
@Pushkar我已经简要地解释了一遍。这可能会帮助你。 –