嗨我正在使用json向我的表发送一个歌曲列表.json响应会很好,直到控制器url.But当我尝试迭代通过它和把细节放在我的表中我得到这个错误。未捕获的类型错误:undefiened不是JSON响应的函数
$(window).load(function(){
$.get("/MusicPlayer/getSongList", function(data){
var library = data;
listSongs(library);
});
});
function listSongs(library){
var table = $("#table");
var row;
$("#table tbody").remove();
library.forEach(function(song){ ***/*this is the line where there is error. */***
row = $("<tr></tr>");
$("<td />").addClass("song-select").append($("<input
/>").attr({type:"checkbox",class:"checkbox",value:song.title})).appendTo(row);
$("<td>"+song.title+"</td>").appendTo(row);
$("<td>"+song.album+"</td>").appendTo(row);
$("<td>"+song.artist+"</td>").appendTo(row);
$("<td>"+song.rating+"</td>").appendTo(row);
$("<td>"+song.composer+"</td>").appendTo(row);
$("<td>"+song.genre+"</td>").appendTo(row);
row.click(viewFunction());
row.appendTo(table);
});
[
{
"title": "15 - Jacob's Theme.mp3",
"album": "The Twilight Saga - Eclipse",
"artist": "Howard Shore",
"rating": "2",
"composer": "carter ruwell",
"genre": "Soundtrack"
},
{
"title": "07_-_Vennante.mp3",
"album": "Andala Rakshasi (2012)",
"artist": "Ranjith",
"rating": "0",
"composer": "Rathan",
"genre": "TeluguMusic"
},
{
"title": "08. One Simple Idea.mp3",
"album": "Inception (OST)",
"artist": "Hans Zimmer",
"rating": "0",
"composer": "null",
"genre": "?????????"
}
]
在回调中做一个'console.log(data)'。显示什么? – Ryan 2014-12-04 07:05:44