初始化参数不同

Question

多个变量我在Python 3以下代码：

x = [(''.join(random.choices(string.ascii_lowercase, k=7))) for _ in range(5)] 

有没有更好的方式与不同的K值和范围初始化多个（5+）名单（）？

例如：

y = [(''.join(random.choices(string.ascii_lowercase, k=3))) for _ in range(5)] 
z = [(''.join(random.choices(string.ascii_lowercase, k=7))) for _ in range(2)] 
a = [(''.join(random.choices(string.ascii_lowercase, k=4))) for _ in range(3)] 
b = [(''.join(random.choices(string.ascii_lowercase, k=3))) for _ in range(5)] 
c = [(''.join(random.choices(string.ascii_lowercase, k=1))) for _ in range(3)] 

Answer 1

把列表中理解的功能和用途反复：

def func(k, r): 
    return [(''.join(random.choices(string.ascii_lowercase, k=k))) for _ in range(r)] 

---

y = func(3, 5) 
... 
c = func(1, 3) 

如果你有两个列表k和r值，你可以这样做：

y,..., c = (func(*t) for t in zip(lst_k, lst_r)) 

或者更好的保证数据的结构列表的列表不用担心目标在LHS数量：

super_list = [func(*t) for t in zip(lst_k, lst_r)] 

Answer 2

肯定的是：参数化的参数：

import random 
import string 

k_val = [3, 7, 4, 3, 1] 
r_val = [5, 2, 3, 5, 3] 

x = [[(''.join(random.choice(string.ascii_lowercase, k=k_val[i]))) 
      for _ in range(r_val[i])] for i in range (len(r_val)) ]