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我想通过JSON首次制作一个简单的WCF RESTful。我在下面有我的界面,但是我将调用哪个URL来调用MemberLogon()方法?WCF RESTful服务配置获取404
我认为这将是这样的:
http://localhost:49701/Exchange.svc/?membershipNumber=6519548&blah=abc
但我得到一个404。我有一种感觉是,在我的web.config我的服务configuraiton做。帮帮我!
我的接口和类是:
[ServiceContract]
public interface IExchange
{
[System.ServiceModel.OperationContract(Name = "MemberLogon")]
[WebInvoke(UriTemplate = "/?membershipNumber={membershipNumber}&blah={blah}", Method = "GET", ResponseFormat = WebMessageFormat.Json)]
Member MemberLogon(string membershipNumber, string blah);
}
[System.Runtime.Serialization.DataContract]
public class Member
{
[System.Runtime.Serialization.DataMember]
public string Username { get; set; }
}
配置为:
<system.serviceModel>
<behaviors>
<serviceBehaviors>
<behavior name="MyNamespace.MyClass.ExchangeBehavior">
<serviceMetadata httpGetEnabled="true" />
<serviceDebug includeExceptionDetailInFaults="false" />
</behavior>
</serviceBehaviors>
</behaviors>
<services>
<service behaviorConfiguration="MyNamespace.MyClass.ExchangeBehavior" name="MyNamespace.MyClass.Exchange">
<endpoint address="" binding="webHttpBinding" contract="MyNamespace.MyClass.IExchange" />
</service>
</services>
我刚刚得到它正确地使用这个网址与你的配置调用:HTTP://本地主机:49701/Exchange.svc/membershipNumber = 6519548&等等= ABC,但我怎么能指定的方法调用(如调用MemberLogon )? – AshesToAshes 2012-04-08 17:32:22
从头开始评论 - 你是明星:)我只需要修改UriTemplate。非常感谢。 – AshesToAshes 2012-04-08 17:36:26