1
我的情况就像，我必须为创建一个脚本，它随机抽取10个用户进行登录和注销。 我写的代码登录了同一个用户10次，它不需要随机数。如何做到这一点？如何随用随机用户登录gatling？
以下是我的代码输出相同的用户登录10次，而不是采取不同的用户。
// Login and Logout random users
import scala.concurrent.duration._
import java.util.concurrent.ThreadLocalRandom
import io.gatling.core.Predef._
import io.gatling.http.Predef._
import io.gatling.jdbc.Predef._
class random extends Simulation {
val testServerUrl = System.getProperty("Url", "https://url")
val username = System.getProperty("username", "TestUser")
val password = System.getProperty("password", "password")
val userCount = Integer.getInteger("userCount", 10).toInt
val startNum = Integer.getInteger("EndNumber", 1).toInt
val endNum = Integer.getInteger("EndNumber", 100).toInt
val httpProtocol = http
.baseURL(testServerUrl)
val scn = scenario("random")
.exec(http("Login")
.post("/security_check")
.headers(headers_9)
.formParam("j_username", username + ThreadLocalRandom.current.nextInt(startNum, endNum))
.formParam("j_password", password)
.resources(
http("Fetch_IDs")
.get("/desktop/s_nav.jsp")
.check(regex("""current_account_id=(\d+)""").saveAs("accountID"))
.check(regex("""current_workspace_id=(\d+)""").saveAs("workspaceID"))
.headers(headers_5)
))
.exec(http("Logout")
.post("/logoutcontroller")
.headers(headers_9)
.formParam("action", "logout")
.formParam("undefined", "")
.formParam("current_account_id", "${accountID}")
.formParam("current_workspace_id", "${workspaceID}"))
setUp(scn.inject(atOnceUsers(userCount))).protocols(httpProtocol)
}