无法更新我的MySQL分贝

所以我有我的MySQL查询问题。当我尝试更改“电子邮件”列时，它会经历所有if语句，并且仅显示我已成功更改了电子邮件，但由于某些原因它没有成功。请告诉我错误在哪里......可能是愚蠢的，但由于某种原因我找不到它。无法更新我的MySQL分贝

这里是编码：

<?php 
 
session_start(); 
 
include 'connection/db_connect.php'; 
 
$sessionname = $_SESSION['name']; 
 
$sql = "SELECT * FROM registered WHERE userName='$sessionname'"; 
 
$result = mysqli_query($conn, $sql); 
 
$currentprofile = "Your profile"; 
 
$selectedprofile = "<h1>Your profile</h1>"; 
 
while($row = mysqli_fetch_array($result, MYSQL_ASSOC)){ 
 
\t $username = $row['userName']; 
 
\t $password = $row['password']; 
 
\t $email = $row['email']; 
 
\t $sessionid = $row['id']; 
 
} 
 
$erroremail = null; 
 
$changeEmail = $_POST['changeEmail']; 
 
$changeEmailValue = $_POST['changeEmailValue']; 
 
$changePassword = $_POST['changePassword']; 
 
$changePasswordNew = $_POST['changePasswordNew']; 
 
$changePasswordRepeat = $_POST['changePasswordRepeat']; 
 

 
if(isset($changeEmail)){ 
 
\t if(!empty($changeEmailValue)){ 
 
\t \t $sqlemail = "SELECT email FROM registered where email='$changeEmailValue'"; 
 
\t \t $resultemail = mysqli_query($conn, $sqlemail); 
 
\t \t if(mysqli_num_rows($resultemail) >= 1){ 
 
\t \t \t $erroremail = "<p style='color:red;'>This email is already in use by another user!</p>"; 
 
\t \t } else { 
 
\t \t \t $sqlemailtwo = "UPDATE registered SET email='$changeEmailValue' WHERE id='$sessionid'"; 
 
\t \t \t mysql_query($conn, $sqlemailtwo); 
 
\t \t \t $erroremail = "<p style='color:green;'>You updated ypur email successfully!</p>"; 
 
\t \t } 
 
\t } else { 
 
\t \t $erroremail = "<p style='color:red;'>You didn't enter email!</p>"; 
 
\t } 
 
} 
 

 
if($sessionname == null){ 
 
\t header ('Location: index.php'); // proverka za login 
 
} 
 
?> 
 
<html> 
 
<head> 
 
\t <title><?php echo $currentprofile; ?></title> 
 
\t <style> 
 
\t </style> 
 
</head> 
 
<body> 
 
<div> 
 
<?php echo "Hello, ".$username; ?> | <a href='logout.php'>Logout</a> 
 
<div style='width: 230px; height: 100%;'> 
 

 
<span><?php echo $selectedprofile; ?></span> 
 
<br> 
 
\t Email: 
 
\t <?php echo $erroremail; ?> 
 
\t <form method='post' action='?=changeEmail'> 
 
\t \t <input type='email' name='changeEmailValue' value='<?php echo $email; ?>'> 
 
\t \t <input type='submit' name='changeEmail' value='Change'> 
 
\t </form> 
 
<hr> 
 
\t Password: 
 
\t <form method='post' action='?=changePassword'> 
 
\t \t <input type='password' name='changePasswordCurrent' value='' placeholder='Your current password'> 
 
\t \t <input type='password' name='changePasswordNew' value='' placeholder='New password'> 
 
\t \t <input type='password' name='changePasswordRepeat' value='' placeholder='Repeat new password'> 
 
\t \t <input type='submit' name='changePassword' value='Change'> 
 
\t </form><br> 
 
<hr> 
 
\t Your IP adress: 
 
\t <?php ?> 
 
</div> 
 

 
</body> 
 
</html>

来源

2016-11-20 simplepickup

我认为这是 '我' 的问题。你可以改变

mysql_query($conn, $sqlemailtwo); to mysqli_query($conn, $sqlemailtwo);

来源

2016-11-20 14:06:38

不仅如此，而且'MYSQL_ASSOC'也。 –

无法更新我的MySQL分贝

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