如何将CSV列表中的URL传递给python GET请求

我有一个CSV文件，其中包含一个Google扩展名ID列表。
我正在写一个代码，将读取信息ID，添加网络存储器网址，然后进行基本的GET请求：如何将CSV列表中的URL传递给python GET请求

import csv 
import requests 

with open('small.csv', 'rb') as f: 
    reader = csv.reader(f) 
    for row in reader: 
     urls = "https://chrome.google.com/webstore/detail/" + row[0] 
     print urls 
     r = requests.get([urls])

在以下回溯这段代码运行的结果：

Traceback (most recent call last): 
    File "C:\Users\tom\Dropbox\Python\panya\test.py", line 9, in <module> 
    r = requests.get([urls]) 
    File "C:\Python27\lib\site-packages\requests\api.py", line 69, in get 
    return request('get', url, params=params, **kwargs) 
    File "C:\Python27\lib\site-packages\requests\api.py", line 50, in request 
    response = session.request(method=method, url=url, **kwargs) 
    File "C:\Python27\lib\site-packages\requests\sessions.py", line 465, in request 
    resp = self.send(prep, **send_kwargs) 
    File "C:\Python27\lib\site-packages\requests\sessions.py", line 567, in send 
    adapter = self.get_adapter(url=request.url) 
    File "C:\Python27\lib\site-packages\requests\sessions.py", line 641, in get_adapter 
    raise InvalidSchema("No connection adapters were found for '%s'" % url) 
InvalidSchema: No connection adapters were found for '['https://chrome.google.com/webstore/detail/blpcfgokakmgnkcojhhkbfbldkacnbeo']'

如何修改代码，使其能够接受列表中的网址，并发出GET请求？

来源

2015-10-19 Tom Kidron

requests.get需要一个字符串，但你创造和传递一个列表[urls]

r = requests.get([urls])

更改它只是

r = requests.get(urls)

，它应该工作。

来源

2015-10-23 12:44:32 miles82

如何将CSV列表中的URL传递给python GET请求

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