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我试图通过Indy 10.5.8在多部分/表单数据中使用POST发送文件。我正在使用Delphi XE2，并且我一直在尝试将文件发布到服务器。这是杉杉的时间我已经试过这一点，因为我与印经验是非常有限的，我把下面的代码片段：在使用Indy进行POST时使用标题垃圾10.5.8
unit MsMultiPartFormData;
interface
uses
SysUtils, Classes;
const
CONTENT_TYPE = 'multipart/form-data; boundary=';
CRLF = #13#10;
CONTENT_DISPOSITION = 'Content-Disposition: form-data; name="%s"';
FILE_NAME_PLACE_HOLDER = '; filename="%s"';
CONTENT_TYPE_PLACE_HOLDER = 'Content-Type: %s' + crlf + crlf;
CONTENT_LENGTH = 'Content-Length: %d' + crlf;
type
TMsMultiPartFormDataStream = class(TMemoryStream)
private
FBoundary: string;
FRequestContentType: string;
function GenerateUniqueBoundary: string;
public
procedure AddFormField(const FieldName, FieldValue: string);
procedure AddFile(const FieldName, FileName, ContentType: string; FileData: TStream); overload;
procedure AddFile(const FieldName, FileName, ContentType: string); overload;
procedure PrepareStreamForDispatch;
constructor Create;
property Boundary: string read FBoundary;
property RequestContentType: string read FRequestContentType;
end;
implementation
{ TMsMultiPartFormDataStream }
constructor TMsMultiPartFormDataStream.Create;
begin
inherited;
FBoundary := GenerateUniqueBoundary;
FRequestContentType := CONTENT_TYPE + FBoundary;
end;
procedure TMsMultiPartFormDataStream.AddFile(const FieldName, FileName,
ContentType: string; FileData: TStream);
var
sFormFieldInfo: string;
Buffer: PChar;
iSize: Int64;
begin
iSize := FileData.Size;
sFormFieldInfo := Format(CRLF + '--' + Boundary + CRLF + CONTENT_DISPOSITION +
FILE_NAME_PLACE_HOLDER + CRLF + CONTENT_LENGTH +
CONTENT_TYPE_PLACE_HOLDER, [FieldName, FileName, iSize, ContentType]);
{so: boundary + crlf + content-disposition+file-name-place-holder}
Write(Pointer(sFormFieldInfo)^, Length(sFormFieldInfo));
FileData.Position := 0;
GetMem(Buffer, iSize);
try
FileData.Read(Buffer^, iSize);
Write(Buffer^, iSize);
finally
FreeMem(Buffer, iSize);
end;
end;
procedure TMsMultiPartFormDataStream.AddFile(const FieldName, FileName,
ContentType: string);
var
FileStream: TFileStream;
begin
FileStream := TFileStream.Create(FileName, fmOpenRead or fmShareDenyWrite);
try
AddFile(FieldName, FileName, ContentType, FileStream);
finally
FileStream.Free;
end;
end;
procedure TMsMultiPartFormDataStream.AddFormField(const FieldName,
FieldValue: string);
var
sFormFieldInfo: string;
begin
sFormFieldInfo := Format(CRLF + '--' + Boundary + CRLF + CONTENT_DISPOSITION + CRLF + CRLF +
FieldValue, [FieldName]);
Write(Pointer(sFormFieldInfo)^, Length(sFormFieldInfo));
end;
function TMsMultiPartFormDataStream.GenerateUniqueBoundary: string;
begin
Result := '---------------------------' + FormatDateTime('mmddyyhhnnsszzz', Now);
end;
procedure TMsMultiPartFormDataStream.PrepareStreamForDispatch;
var
sFormFieldInfo: string;
begin
sFormFieldInfo := CRLF + '--' + Boundary + '--' + CRLF;
Write(Pointer(sFormFieldInfo)^, Length(sFormFieldInfo));
Position := 0;
end;
end.
我打电话这样的代码：
function PostFile(filename, apikey: string): boolean;
var
ResponseStream: TMemoryStream;
MultiPartFormDataStream: TMsMultiPartFormDataStream;
begin
// Form5.IdHTTP1.HandleRedirects := true;
Form5.idHTTP1.ReadTimeout := 0;
// Form5.idHTTP1.IOHandler.LargeStream := True;
Result := false;
MultiPartFormDataStream := TMsMultiPartFormDataStream.Create;
ResponseStream := TMemoryStream.Create;
try
try
Form5.IdHttp1.Request.ContentType := MultiPartFormDataStream.RequestContentType;
MultiPartFormDataStream.AddFormField('apikey', apikey);
MultiPartFormDataStream.AddFile('file', filename, 'multipart/form-data');
MultiPartFormDataStream.PrepareStreamForDispatch;
MultiPartFormDataStream.Position := 0;
Form5.IdHTTP1.Post('http://www.updserver.tld/api//file/save', MultiPartFormDataStream, ResponseStream);
MultiPartFormDataStream.SaveToFile(ExtractFilePath(Application.ExeName) + 'a.txt');
Result := true;
except
on E:Exception do
begin
Form5.Close;
ShowMessage('Upload failed! '+E.Message);
end;
end;
finally
MultiPartFormDataStream.Free;
ResponseStream.Free;
end;
end;
文件被发送，但被服务器拒绝。发送的数据的仔细检查发现，得到的数据有所损坏（我怀疑编码问题） - 我所看到的是：
POST /api/file/save HTTP/1.0
Connection: keep-alive
Content-Type: multipart/form-data; boundary=---------------------------071312151405662
Content-Length: 11040172
Host: www.updserver.tld
Accept: text/html, */*
Accept-Encoding: identity
User-Agent: Mozilla/3.0 (compatible; Indy Library)
.
.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.0.7.1.3.1.2.1.5.1.4.0.5.6.6.2.
.
.C.o.n.t.e.n.t.-.D.i.s.p.o.s.i.t.i.o.n.:. .f.o.r.m.-.d.a.t.a.;. .n
.
.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.-.0.7.1.3.1.2.1.5.1.4.0.5.6.6.2.
.
.C.o.n.t.e.n.t.-.D.i.s.p.o.s.i.t.i.o.n.:. .f.o.r.m.-.d.a.t.a.;. .n.a.m.e.=.".f.i.l.e.".;. .f.i.l.e.n.a.m.e.=.".C.:.\.U.s.e........................>.......................................................v.......:...;...<.......[.......v.......................t.......o.......z............
...
...
定期头，从工作的Python客户端发送的，是这样的：
POST https://updserver.tld/api/file/save HTTP/1.0
content-type: multipart/form-data; boundary=---------------------------071312151405662
content-length: 6613364
---------------------------071312151405662
Content-Disposition: form-data; name="apikey"
ac36fae9a406596[rest-of-api-key-goes-here]17966c42b60c8c4cd
---------------------------071312151405662
Content-Disposition: form-data; name="file"; filename="C:\Users\User\Desktop\Project1.exe"
Content-Type: application/octet-stream
有关我在做什么错的任何想法？
在此先感谢。
有您为什么要写一个模仿Indy的'TIdMultipartFormDataStream'类自己的T流类，而不是仅仅使用Indy的'TIdMultipartFormDataStream'类的，是什么原因呢？ – 2012-07-16 21:03:12
不，这只是样本代码的不幸选择。我立刻将其删除，并将其替换为Indy的原创课程，并且工作正常。 – 2012-07-17 07:30:28