自动读取多个文件没有手动文件命名

Question

我有一个目录包含50个文件我想逐一阅读它们并与其他文件比较 - 这是固定的。我正在使用glob.blob。但它没有奏效。

这里我是如何读取所有文件的。相反，path = '*.rbd'如果我给它的文件名如path = run-01.rbd它的工作原理。

path = '*.rbd' 

path = folder + path 
files=sorted(glob.glob(path)) 

完整代码

import glob 
from itertools import islice 
import linecache 

num_lines_nonbram = 1891427 

bits_perline = 32 

total_bit_flips = 0 

num_bit_diff_flip_zero = 0 
num_bit_diff_flip_ones = 0 
folder = "files/" 

path = '*.rbd' 

path = folder + path 
files=sorted(glob.glob(path)) 

original=open('files/mull-original-readback.rbd','r') 

#source1 = open(file1, "r") 

for filename in files: 
del_lines = 101 

with open(filename,'r') as f: 
    i=1 
    while i <= del_lines: 
    line1 = f.readline() 
    lineoriginal=original.readline() 
    i+=1 
    i=0 
    num_bit_diff_flip_zero = 0 
    num_bit_diff_flip_ones = 0 
    num_lines_diff =0 

    i=0 
    j=0 
    k=0 
    a_write2 = "" 
    while i < (num_lines_nonbram-del_lines): 
     line1 = f.readline() 
     lineoriginal = original.readline() 
     while k < bits_perline: 
       if ((lineoriginal[k] == line1[k])): 
        a_write2 += " " 
       else: 
        if (lineoriginal[k]=="0"): 
        #if ((line1[k]=="0" and line1[k]=="1")): 

         num_bit_diff_flip_zero += 1 
        if (lineoriginal[k]=="1"): 
        #if ((line1[k]=="0" and line1[k]=="1")): 

         num_bit_diff_flip_ones += 1 

        #if ((line1[k]==1 and line1[k]==0)): 
         #a_write_file2 = str(i+1) + " " + str(31-k) + "\n" + a_write_file2 
         #a_write2 += "^" 
         #num_bit_diff_flip_one += 1 
        # else: 
        # a_write2 += " " 
       k+=1 


       total_bit_flips=num_bit_diff_flip_zero+num_bit_diff_flip_ones 
     i+=1 

     k=0 
i = 0 
print files 
print "Number of bits flip zero= %d" %num_bit_diff_flip_zero +"\n" +"Number of bits flip one= %d" %num_bit_diff_flip_ones +"\n" "Total bit flips = %d " %total_bit_flips 


f.close() 
original.close() 

Answer 1

您可以使用os模块在一个目录列表第一的一切（包括文件和模块），然后使用一个Python生成器来过滤出的文件。然后，您可以使用第二个Python生成器来过滤具有特定扩展名的文件。有可能是做的更有效的方法，但这个工程：

import os 

def main(): 

    path = './' # The path to current directory 

    # Go through all items in the directory and filter out files 
    files = [file for file in os.listdir(path) if 
os.path.isfile(os.path.join(path, file))] 

    # Go through all files and filter out files with .txt (for example) 
    specificExtensionFiles = [file for file in files if ".txt" in file] 

    # Now specificExtensionFiles is a generator for .txt files in current 
    # directory which you can use in a for loop 
    print (specificExtensionFiles) 


if __name__ == '__main__': 
    main() 

更多参考： How do I list all files of a directory?

---

Answer 2

的问题是，你不打算回originalfile每当开始您将开始与for filename in files:循环中的下一个文件进行比较。最简单的解决方案是：

original.seek(0) 

在该循环的开始。

您也可以在循环之前将整个文件读入列表中，并使用该文件而不是重复读取文件。

如果您只想处理部分文件，则可以将文件读入列表中，然后使用列表切片获取所需的行。

您也不应该设置num_bit_diff_flip_zero和num_bit_diff_flip_one到0每次通过循环，因为这些应该是所有文件之间的总和。

with open('files/mull-original-readback.rbd','r') as original: 
    original_lines = list(original)[del_lines:num_lines_nonbram] 

for filename in files: 
    with open(file, 'r') as f: 
     lines = list(f)[del_lines:num_lines_nonbram] 
    for lineoriginal, line1 in zip(original_lines, lines): 
     for k in range(bits_perline): 
      if lineoriginal[k] == line1[k]: 
       a_write2 += " " 
      elif lineoriginal[k] == "0" 
       num_bit_diff_flip_zero += 1 
      else: 
       num_bit_diff_flip_ones += 1 

total_bit_flips = num_bit_diff_flip_zero + num_bit_diff_flip_ones