解析：一次检索不同表格中的所有数据

Question

我试图从不同表格中获取所有数据，因此我尝试使用此方法。但是，我明白for循环是同步的，因此当解析正在获取数据时，循环不会停止。有没有人知道如何解决它？有没有可能有助于这种情况的解析方法或某些意图服务？

private void getAllInformation(){ 
    String controlName; 
    for(int i=0; i<3;i++){ 
     if(i==0){ 
      controlName = AppConfiguration.strEvent; 
     } 
     else if(i==1){ 
      controlName = AppConfiguration.strStore; 
     } 
     else if (i==2){ 
      controlName = AppConfiguration.strPromotion; 
     } 
     else{ 
      return; 
     } 

     ParseQuery<ParseObject> query = ParseQuery.getQuery(controlName); 
     query.findInBackground(new FindCallback<ParseObject>() { 
      public void done(List<ParseObject> objectList, ParseException e) { 
       if(e!=null){ 
        Toast.makeText(getApplicationContext(),"Error Loading.Please Try Again",Toast.LENGTH_LONG).show(); 
        return; 
       } 
       if (objectList!= null) { 
        Toast.makeText(getApplicationContext(),"Success",Toast.LENGTH_LONG).show(); 
        ParseObject.pinAllInBackground(objectList); 
       } 
       else{ 
        Toast.makeText(getApplicationContext(),"Some Data is null!",Toast.LENGTH_LONG).show(); 
       } 


      } 

     }); 

    } 


//  getAllOfflineInformation(); 
} 

Answer 1

您可以使用锁：

Object lock = new Object(); 

ParseQuery<ParseObject> query = ParseQuery.getQuery(controlName); 
     query.findInBackground(new FindCallback<ParseObject>() { 
      public void done(List<ParseObject> objectList, ParseException e) { 
  synchronized (lock) { 
            lock.notifyAll(); 
        } 
       if(e!=null){ 
        Toast.makeText(getApplicationContext(),"Error Loading.Please Try Again",Toast.LENGTH_LONG).show(); 
        return; 
       } 
       if (objectList!= null) { 
        Toast.makeText(getApplicationContext(),"Success",Toast.LENGTH_LONG).show(); 
        ParseObject.pinAllInBackground(objectList); 
       } 
       else{ 
        Toast.makeText(getApplicationContext(),"Some Data is null!",Toast.LENGTH_LONG).show(); 
       } 


      } 

     }); 

synchronized (lock) { 
    lock.wait(); 
}