0
我正在使用XMLWriter创建聊天xml。该文件应通过将收到的消息追加到现有的聊天文件中进行更新。例如在下面的xml文件中,我想在msg_id = 5的节点之后附加一个新的消息节点。我的问题是我得到的代码创建了一个新的XMl文件。请指教。C#将节点附加到现有的xml文件
我的XML文件
<?xml version="1.0" encoding="utf-8"?>
<client>
<name>client_name</name>
<url>client_name.myapp.com</url>
<ver>1</ver>
<conversation>
<sender_id>5</sender_id>
<fname>First</fname>
<mname>Middle</mname>
<lname>Last</lname>
<last_seen>l, d-M-y H:i:s T</last_seen>
<messages>
<message>
<msg_id>1</msg_id>
<recepient_id />
<message>Lorem ipsum dolor sit amet, consectetuer adipiscing elit.</message>
</message>
<message>
<msg_id>2</msg_id>
<recepient_id />
<message>Lorem ipsum dolor sit amet, consectetuer adipiscing elit.</message>
</message>
<message>
<msg_id>3</msg_id>
<recepient_id />
<message>Lorem ipsum dolor sit amet, consectetuer adipiscing elit.</message>
</message>
<message>
<msg_id>4</msg_id>
<recepient_id />
<message>Lorem ipsum dolor sit amet, consectetuer adipiscing elit.</message>
</message>
<message>
<msg_id>5</msg_id>
<recepient_id />
<message>Lorem ipsum dolor sit amet, consectetuer adipiscing elit.</message>
</message>
</messages>
</conversation>
</client>
我的代码
chat = JsonConvert.DeserializeObject<Chat>(json_data);
for (int conversations_count = 0; conversations_count < chat.conversations.Count; conversations_count++) // Loop through List with for
{
var conversation = chat.conversations[conversations_count];
var conversation_file_name = conversation.fname + " " + conversation.mname + " " + conversation.lname;
var messages = conversation.messages;
if (File.Exists(conversation_file_name))
{
using (XmlWriter writer = XmlWriter.Create(conversation_file_name+".xml"))
{
writer.WriteStartDocument();
writer.WriteStartElement("client");
writer.WriteElementString("name", "client_name");
writer.WriteElementString("url", "client_name.myapp.com");
writer.WriteElementString("ver", "1.0");
writer.WriteStartElement("conversation");
writer.WriteElementString("sender_id", conversation.sender_id.ToString());
writer.WriteElementString("fname", conversation.fname.ToString());
writer.WriteElementString("mname", conversation.mname.ToString());
writer.WriteElementString("lname", conversation.lname.ToString());
writer.WriteElementString("last_seen", conversation.last_seen.ToString());
writer.WriteStartElement("messages");
for (int messages_count = 0; messages_count < messages.Count; messages_count++) // Loop through List with for
{
writer.WriteStartElement("message");
writer.WriteElementString("msg_id", messages[messages_count].msg_id.ToString());
writer.WriteElementString("recepient_id", messages[messages_count].recepient_id.ToString());
writer.WriteElementString("message", messages[messages_count].message.ToString());
writer.WriteEndElement();
}
writer.WriteEndElement();
writer.WriteEndElement();
writer.WriteEndElement();
writer.WriteEndDocument();
}
}
}
这答案对我有用http:// stack overflow.com/questions/20922835/appending-an-existing-xml-file-with-xmlwriter?rq=1 – 2014-09-13 11:31:37
您是否必须使用'XmlWriter'来执行此操作,或者您可以移动到更简单的API,如'XDocument'或'XmlDocument '?你使用的是什么.NET框架版本? – har07 2014-09-13 12:40:14
我正在使用.Net 2.0 – sammyukavi 2014-09-13 13:48:13