从字符串获取日期时间

Question

我怎样才能得到这2个日期在这个字符串？

从2011-08-01 00:00至2011-08-31 23:59（当地时间）2011-07-15 20:43

我想这个日期2011-08 -01 00:00和23:59 2011-08-31

Answer 1

日期1：@"(?<=FROM)\d{4}-\d{2}-\d{2} \d{2}:\d{2}"

日期2：@"(?<=TO)\d{4}-\d{2}-\d{2} \d{2}:\d{2}"

Answer 2

这应该做到这一点：

var dateRegex = @"\d{4}-\d{2}-\d{2} \d{2}:\d{2}"; 
    var regex = new Regex(@"FROM (" + dateRegex + @") TO (" + dateRegex + @") \(Local Time\) .*$"); 
    var text = @"FROM 2011-08-01 00:00 TO 2011-08-31 23:59 (Local Time) 2011-07-15 20:43"; 
    var match = regex.Match(text); 
    if (match.Success) 
    { 
     Console.WriteLine("1: " + match.Groups[1].Value.ToString()); 
     Console.WriteLine("2: " + match.Groups[2].Value.ToString()); 
    } 

Answer 3

这应该给你你需要什么（我做这样的假设字符串将始终以这种格式 - 所以没有错误处理）：

string text = "FROM 2011-08-01 00:00 TO 2011-08-31 23:59 (Local Time) 2011-07-15 20:43"; 

Regex r = new Regex(@"(?<=FROM)(.*?)(?=\()", 
        RegexOptions.Singleline | RegexOptions.IgnoreCase); 

string[] dates = r.Split(text).GetValue(1).ToString().Trim().Split(' '); 

string date1 = dates[0].ToString() + " " + dates[1].ToString(); 
string date2 = dates[3].ToString() + " " + dates[4].ToString();