DataGridView selectedRow属性没有获得数据，如果我双击行？

Question

我点击double dataGridView的任何一行。没有得到数据点击行数据：

    private void gwStudies_CellDoubleClick(object sender, DataGridViewCellEventArgs e) 
     { 
      GoruntuyuAc(); 
     } 

private void GoruntuyuAc() 
     { 
      olduid = ""; 
      DataRowView ro = (gwStudies.SelectedRows[0].DataBoundItem as DataRowView); 
      string uid = ""; 
      uid = ro["StudyInstanceUid"].ToString(); 
      string tarih = ""; 
      DateTime t1 = Convert.ToDateTime(ro["StudyDate"]); 
      //........ 
      //............ 
     }

上（gwStudies.SelectedRows [0]作为.DataBoundItem DataRowView的）错误数据;
图片：alt text http://i42.tinypic.com/n6utt2.png

Answer 1

我不太确定，但我认为选择发生在双击事件后。

Answer 2

这里你必须传递GoruntuyuAc（int row，int col）函数中的行索引和列索引。 像GoruntuyuAc（e.RowIndex，e.ColumnIndex）;

Answer 3

您可以订阅SelectionChanged事件或尝试这样的事：

private void gwStudies_CellDoubleClick(object sender, DataGridViewCellEventArgs e) 
     { 
      olduid = ""; 
      DataRowView ro = (gwStudies.Rows[e.RowIndex].DataBoundItem as DataRowView); 
      string uid = ""; 
      uid = ro["StudyInstanceUid"].ToString(); 
      string tarih = ""; 
      DateTime t1 = Convert.ToDateTime(ro["StudyDate"]); 
      //........ 
      //............ 
     } 

Answer 4

只给你一个最佳实践，为了确保对点击的DataGridView，你应该投发件人如下

void transactionsGridView_CellDoubleClick(object sender, DataGridViewCellEventArgs e) 
    { 
     DataGridView senderDataGrid = (DataGridView)sender; 
     YourBoundModelClass row = 
      (senderDataGrid.Rows[e.RowIndex].DataBoundItem as YourBoundModelClass); 
     //... 
    } 

这也是强类型。