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我要解决的问题是:如何解决线性规划问题,使用JOptimizer Java API提供备选最优解决方案?
/** Maximize 4x+3Y
* Subject to
* 8x+6y <= 25
* 3x+4y <= 15
* x,y >= 0
*/
理论上这个问题的最佳LP解决方案具有无限#。
所有需要的库,在我的谷歌提供的依赖关系驱动: https://drive.google.com/file/d/0B84k1fZRHSMdak00TjZKNXBKSFU/view?usp=sharing
我的代码:
package testJOptimizer;
import com.joptimizer.functions.ConvexMultivariateRealFunction;
import com.joptimizer.functions.LinearMultivariateRealFunction;
import com.joptimizer.optimizers.JOptimizer;
import com.joptimizer.optimizers.OptimizationRequest;
/**
*
* @author K.P.L.Kanchana
*/
public class test_4_alternateOptimum {
/**
* @param args the command line arguments
*/
public static void main(String[] args){
// BasicConfigurator.configure();
// Objective function (plane)
LinearMultivariateRealFunction objectiveFunction = new LinearMultivariateRealFunction(new double[] {-4.0, -3.0}, 0); // maximize 4x+3y
//inequalities (polyhedral feasible set G.X<H)
ConvexMultivariateRealFunction[] inequalities = new ConvexMultivariateRealFunction[4];
// 8x+6y <= 25
inequalities[0] = new LinearMultivariateRealFunction(new double[]{8.0, 6.0}, -25); // 8x+6y-25<=0
// 3x+4y <= 15
inequalities[1] = new LinearMultivariateRealFunction(new double[]{1.0, 4.0}, -15); // 3x+4y-15<=0
// x >= 0
inequalities[2] = new LinearMultivariateRealFunction(new double[]{-1.0, 0.0}, 0);
// y >= 0
inequalities[3] = new LinearMultivariateRealFunction(new double[]{0.0, -1.0}, 0);
//optimization problem
OptimizationRequest or = new OptimizationRequest();
or.setF0(objectiveFunction);
or.setFi(inequalities);
//or.setInitialPoint(new double[] {0.0, 0.0});//initial feasible point, not mandatory
or.setToleranceFeas(1.E-9);
or.setTolerance(1.E-9);
//optimization
JOptimizer opt = new JOptimizer();
opt.setOptimizationRequest(or);
try {
int returnCode = opt.optimize();
}
catch (Exception ex) {
ex.printStackTrace();
return;
}
// get the solution
double[] sol = opt.getOptimizationResponse().getSolution();
// display the solution
System.out.println("Length: " + sol.length);
for (int i = 0; i < sol.length; i++) {
System.out.println("answer " + (i+1) + ": " + (sol[i]));
}
}
}
这是一个数学问题或编程问题?如果数学,那么你在错误的网站。如果编程,告诉我们你试过什么,并解释你有什么问题。现在,它看起来像是“为我工作”的问题,这绝对是StackOverflow的焦点话题。 – Andreas
作为一个数学问题,答案为'0 <= Y <= 45/14','X =(25-6y)/ 8',最大化'4X + 3y'在'12.5'。正如你所说:*无限制#个解决方案。* – Andreas
这是一个数学问题,需要用java解决。我使用了JOptimizer库和我创建的类的数量,这使得使用JOptimizer变得很容易。 –