我正在为我自己的个人休闲和学习项目工作。部分原因是这样的:获取(string#)函数跳过第一个获取请求
#include<stdio.h>
#include<string.h>
wgame()
{
char string3[12], string2[12], string1[12], string4[12], string5[12];
memset (string1, 0, 11);
memset (string2, 0, 11);
memset (string3, 0, 11);
memset (string4, 0, 11);
memset (string5, 0, 11);
printf("reference C correct\n");
printf("Okay, so you want a game. Here's one for you\n\n\n");
printf("This is a word game.\n\n A noun is a person place or thing.\n A verb is
something that you can get up and do.\n A subject is what the conversation is about.\n");
printf("Go ahead, type a subject:\n");
gets(string3);
printf("That's a good one. Now, type a verb:\n");
gets(string2);
printf("How about another:\n");
gets(string4);
printf("Really? Okay. Now, type in a noun:\n");
gets(string1);
printf("Cool. How about typing another noun:\n");
gets(string5);
printf("Allright, here's how your words fit into this game:\n\n\n\n\n");
printf("When the %s was %s the %s %s all the other %s", string1,
string2, string3, string4, string5);
return 4;
}
我的问题是输出跳过第一个“获取(串#)”,并继续到下一个 的“printf()”。有人能告诉我为什么这是吗?
'wgame()'应该是'int wgame(void)'。 *永远不要使用'gets()';它不能安全使用,并且正在从语言中删除。使用有意义的变量名。避免使用“幻数”('11','12')。缩进你的代码。 –