2016-07-06 155 views
-3

我有下面的代码列出文件夹和子文件夹中的所有文件与路径。但我想列出只有特定扩展名的文件(例如:.txt文件)复制具有特定扩展名的文件名的位置

我该怎么做..?

Code: 

Sub Test() 

Call ListFilesInFolder("D:\Downloads", True) 

End Sub 


Sub ListFilesInFolder(ByVal SourceFolderName As String, ByVal IncludeSubfolders As Boolean) 

Dim FSO As Object 
Dim SourceFolder As Object 
Dim SubFolder As Object 
Dim FileItem As Object 
Dim r As Long 
Set FSO = CreateObject("Scripting.FileSystemObject") 
Set SourceFolder = FSO.GetFolder(SourceFolderName) 
r = Range("A65536").End(xlUp).Row + 1 
For Each FileItem In SourceFolder.Files 
Cells(r, 1).Formula = FileItem.Name 
Cells(r, 2).Formula = FileItem.Path 
r = r + 1 ' next row number 
X = SourceFolder.Path 
Next FileItem 
If IncludeSubfolders Then 
For Each SubFolder In SourceFolder.SubFolders 
ListFilesInFolder SubFolder.Path, True 
Next SubFolder 
End If 

Set FileItem = Nothing 
Set SourceFolder = Nothing 
Set FSO = Nothing 

End Sub 
+1

你什么都试过? –

+0

可以使用python直接调用的操作系统创建子文件夹列表及其内容 - 请参见http://superuser.com/a/319009 – JBithell

+0

您可能想使用['os.walk'](https ://docs.python.org/3/library/os.html#os.walk)。 – Matthias

回答

0

您可以使用GetExtensionName Method这样的:

Sub ListFilesInFolder(ByVal SourceFolderName As String, ByVal IncludeSubfolders As Boolean) 

Dim FSO As Object 
Dim SourceFolder As Object 
Dim SubFolder As Object 
Dim FileItem As Object 
Dim r As Long 
Set FSO = CreateObject("Scripting.FileSystemObject") 
Set SourceFolder = FSO.GetFolder(SourceFolderName) 
r = Range("A65536").End(xlUp).Row + 1 

For Each FileItem In SourceFolder.Files 
    If FSO.GetExtensionName(FileItem) = "txt" Then 'change txt as you want 
    Cells(r, 1).Formula = FileItem.Name 
    Cells(r, 2).Formula = FileItem.Path 
    r = r + 1 ' next row number 
    End If 
    X = SourceFolder.Path 
Next FileItem 

If IncludeSubfolders Then 
For Each SubFolder In SourceFolder.SubFolders 
ListFilesInFolder SubFolder.Path, True 
Next SubFolder 
End If 

Set FileItem = Nothing 
Set SourceFolder = Nothing 
Set FSO = Nothing 

End Sub 
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