致命的问题查询

Question

我有关于这3个查询一个问题：

select count(*) as rec_count from test_history inner join 
    test_detail on test_history.history_id = test_detail.test_history_id 
    where test_history.history_id in ({$_SESSION['history_ids']}) 
    and test_history.user_id = $userID 

和

select count(*) as correct_answers from test_history inner join test_detail 
    on test_history.history_id = test_detail.test_history_id 
    where test_history.history_id in ({$_SESSION['history_ids']}) and 
    test_history.user_id = $userID and is_correct = 1 

而这一次

select * from test_topics inner join 
    test_topics_link on test_topics.`topic_id` = test_topics_link.`topic_id` 
    where test_topics_link.test_id in ({$_SESSION['ids_tests']}) and percentage > 0 

我一直都想与此错误：

You have an error in your SQL syntax; check the manual that corresponds to your 
MySQL server version for the right syntax to use near ') and 
test_history.user_id = 82' at line 3 

You have an error in your SQL syntax; check the manual that corresponds to your 
MySQL server version for the right syntax to use near ') and 
test_history.user_id = 82 and is_correct = 1' at line 2 

You have an error in your SQL syntax; check the manual that corresponds to your 
MySQL server version for the right syntax to use near ')' at line 1 

You have an error in your SQL syntax; check the manual that corresponds to your 
MySQL server version for the right syntax to use near ') and percentage > 0' at 
line 3 

Answer 1

由于$_SESSION['ids_tests']，我想是一个数组，你应该写implode(',',$_SESSION['ids_test'])，例如，在PHP中它应该是：

$query = "select * from test_topics inner join 
     test_topics_link on test_topics.`topic_id` = test_topics_link.`topic_id` 
     where test_topics_link.test_id in (". 
     implode(',',$_SESSION['ids_tests']).") and percentage > 0";