如何使用XSLT显示来自XML的相同类型的数据

我有下面的XML。

<documentCountryInformation> 
     <countryCode>US</countryCode> 
     <countryName>United States</countryName> 
     <sufficientDocumentation>Conditional</sufficientDocumentation> 
     <sectionInformation> 
      <sectionName>Health</sectionName> 
      <documentParagraph paragraphId="23628"> 
      <paragraphType>Requirement</paragraphType> 
      <paragraphText> 
       <p> 
       Vaccination for 
       <strong>yellow fever</strong> 
       Persons without valid yellow fever certification, if required, are subject to quarantine for a period up to 6 days. 
       </p> 
      </paragraphText> 
      </documentParagraph>    
     </sectionInformation> 
</documentCountryInformation> 
<documentCountryInformation> 
     <countryCode>IN</countryCode> 
     <countryName>India</countryName> 
     <sufficientDocumentation>Conditional</sufficientDocumentation> 
     <sectionInformation> 
      <sectionName>Health</sectionName> 
      <documentParagraph paragraphId="23648"> 
      <paragraphType>Requirement</paragraphType> 
      <paragraphText> 
       <p> 
       Vaccination for 
       <strong>Dengue fever</strong> 
       Persons without valid yellow fever certification, if required, are subject to quarantine for a period up to 3 days. 
       </p> 
      </paragraphText> 
      </documentParagraph>    
     </sectionInformation> 
</documentCountryInformation>

以上是完整的XML的一部分，你可以看到有2个记录同一类型的，现在我已经在上面的例子中XSLT的参数得到了<countryName>我国家名称参数将包含这种类型的数据“美国，印度”，现在我想拆分参数数据，并进一步它将检查具有相同国家名称和显示数据的XML，我的意思是将有循环国名和以下是所需的HTML。

<div class="resultsContainer" id="divTransit"> 
     <h3>Transit - United States (US)</h3>        
     <p> 
     Vaccination for 
     <strong>yellow fever</strong> 
     Persons without valid yellow fever certification, if required, are subject to quarantine for a period up to 6 days. 
     </p> 

     <h3>Transit - India (IN)</h3>        
     <p> 
     Vaccination for 
     <strong>Dengue fever</strong> 
     Persons without valid yellow fever certification, if required, are subject to quarantine for a period up to 3 days. 
     </p> 
</div>

来源

2010-11-22 Manoj Singh

我不明白的问题。这个输出对于XSLT模板匹配看起来很直接，为什么你需要一个“循环”？ – 2010-11-22 05:14:28

它是我的想法是的你是对的，我们可以使用模板匹配，我想我们可能需要，因为我也分裂了参数值。请建议 – 2010-11-22 05:26:11

好问题，+1。查看我的答案，获取完整而简短的解决方案。 :) – 2010-11-22 05:35:48

现在我要拆分的参数数据并进一步将调查具有相同的国名和显示根据数据，我的意思是对国家名称会有是循环，下面是XML 需要的HTML。

没有必要“分裂”的参数值，也没有对任何一种的“循环”。

该转化：

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
<xsl:output omit-xml-declaration="yes" indent="yes"/> 
<xsl:param name="pCountryName" select="'United States,India'"/> 

<xsl:template match="/*"> 
    <div class="resultsContainer" id="divTransit"> 
    <xsl:apply-templates select= 
     "*[contains(concat(',',$pCountryName,','), 
        concat(',',countryName,',') 
       ) 
     ] 
     "/> 
    </div> 
</xsl:template> 

<xsl:template match="documentCountryInformation"> 
    <h3> 
    <xsl:value-of select= 
    "concat('Transit - ', 
      countryName, 
      ' (', 
      countryCode, 
      ')' 
      ) 
    "/> 
    </h3> 
    <xsl:copy-of select="*/*/paragraphText/node()"/> 
</xsl:template> 
</xsl:stylesheet>

当所提供的XML文档施加（包裹在顶部元件成为简洁（wellformed））：

<t> 
    <documentCountryInformation> 
     <countryCode>US</countryCode> 
     <countryName>United States</countryName> 
     <sufficientDocumentation>Conditional</sufficientDocumentation> 
     <sectionInformation> 
      <sectionName>Health</sectionName> 
      <documentParagraph paragraphId="23628"> 
       <paragraphType>Requirement</paragraphType> 
       <paragraphText> 
        <p> 
       Vaccination for 
         <strong>yellow fever</strong> 
       Persons without valid yellow fever certification, if required, are subject to quarantine for a period up to 6 days. 
        </p> 
       </paragraphText> 
      </documentParagraph> 
     </sectionInformation> 
    </documentCountryInformation> 
    <documentCountryInformation> 
     <countryCode>IN</countryCode> 
     <countryName>India</countryName> 
     <sufficientDocumentation>Conditional</sufficientDocumentation> 
     <sectionInformation> 
      <sectionName>Health</sectionName> 
      <documentParagraph paragraphId="23648"> 
       <paragraphType>Requirement</paragraphType> 
       <paragraphText> 
        <p> 
       Vaccination for 
         <strong>Dengue fever</strong> 
       Persons without valid yellow fever certification, if required, are subject to quarantine for a period up to 3 days. 
        </p> 
       </paragraphText> 
      </documentParagraph> 
     </sectionInformation> 
    </documentCountryInformation> 
</t>

产生想要的，正确的结果：

<div class="resultsContainer" id="divTransit"> 
    <h3>Transit - United States (US)</h3> 

    <p> 
       Vaccination for 
         <strong>yellow fever</strong> 
       Persons without valid yellow fever certification, if required, are subject to quarantine for a period up to 6 days. 
        </p> 

    <h3>Transit - India (IN)</h3> 

    <p> 
       Vaccination for 
         <strong>Dengue fever</strong> 
       Persons without valid yellow fever certification, if required, are subject to quarantine for a period up to 3 days. 
        </p> 

</div>

来源

2010-11-22 05:34:52

你可以有一个模板

<xsl:template match="documentCountryInformation[contains($countryName, countryName)]">

来源

2010-11-22 05:37:28 LarsH

请注意，假定没有国家名称可以包含任何其他国家/地区名称。如果你想更强大的匹配，你可以追加分隔符，就像@ Dimitre的答案所示。 – LarsH 2010-11-22 12:30:57

如何使用XSLT显示来自XML的相同类型的数据

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