2017-09-26 120 views
1

嗨即时通讯一个初学者在PHP和MySQL这里如果有问题,它是要么我isset发布提交不工作或我有一些错误在我的编码中,任何人都可以告诉我我在编码中错过了什么?预先感谢您:)

这是我的PHP:

<?php 
$servername = "localhost"; 
$username = "root"; 
$password = ""; 
$dbname = "tempahperalatan"; 

// Create connection 
$conn = mysqli_connect($servername, $username, $password, $dbname); 
// Check connection 
if (!$conn) { 
    die("Connection failed: " . mysqli_connect_error()); 
} 

if (isset($_POST['submit'])) { 

    $pemohon = $_POST['namaPemohon']; 
    $trkhMula = $_POST['tmula']; 
    $trkhAkhir = $_POST['takhir']; 
    $n_program = $_POST['namaProgram']; 
    $lokasi = $_POST['lokasi']; 
    $n_anjuran = $_POST['namaAnjuran']; 
    $catatan = $_POST['catatan']; 

    $sql = "INSERT INTO daftartempah (pemohon, trkhMula, trkhAkhir, n_program, lokasi, n_anjuran, catatan) VALUES ('$namaPemohon', '$tmula', '$takhir', '$namaprogram', '$lokasi', '$namaAnjuran', '$catatan')"; 

    if (mysqli_query($conn, $sql)) { 
     echo "New record created successfully"; 
    } else { 
     echo "Error: " . $sql . "<br>" . mysqli_error($conn); 
    } 
} 


mysqli_close($conn); 
?> 

,这是我的表单:

<form action="page1.php" method="POST"> 

    <div class="form-group row text-left"> 
     <label for="example-text-input" class="col-2 col-form-label">Nama Pemohon: </label> 
     <div class="col-10"> 
      <input class="form-control" type="text" name="namaPemohon" id="namaPemohon"> 
     </div> 
    </div> 

    <div class="form-group row text-left"> 
     <label for="example-date-input" class="col-2 col-form-label">Tarikh Mula: </label> 
     <div class="col-10"> 
      <input class="form-control" type="date" value="0000-00-00" name="tmula" id="tmula"> 
     </div> 
    </div> 

    <div class="form-group row text-left"> 
     <label for="example-date-input" class="col-2 col-form-label">Tarikh Akhir: </label> 
     <div class="col-10"> 
      <input class="form-control" type="date" value="0000-00-00" name="takhir" id="takhir"> 
     </div> 
    </div> 

    <div class="form-group row text-left"> 
     <label for="example-text-input" class="col-2 col-form-label">Nama Program: </label> 
     <div class="col-10"> 
      <input class="form-control" type="text" name="namaProgram" id="namaProgram"> 
     </div> 
    </div> 

    <div class="form-group row text-left"> 
     <label for="example-text-input" class="col-2 col-form-label">Lokasi: </label> 
     <div class="col-10"> 
      <input class="form-control" type="text" name="lokasi" id="lokasi"> 
     </div> 
    </div>    

    <div class="form-group row text-left"> 
     <label for="example-text-input" class="col-2 col-form-label">Dept/Kelab/Anjuran: </label> 
     <div class="col-10"> 
      <select class="form-control" name="namaAnjuran" id="namaAnjuran"> 
       <option name="1" value="1">BK - B. Kewangan</option> 
       <option name="2" value="1">BP - B. Pentadbiran</option> 
       <option name="3" value="1">BPK - B. Perancangan Hal Ehwal Korporat</option> 
       <option name="4" value="1">BPPP - B. Pemb. Penilaian Projek</option> 
       <option name="5" value="1">BPPS - B. Pemb. Projek Sosial</option> 
       <option name="6" value="1">UAD - Unit Audit Dalaman</option> 
       <option name="7" value="1">PWT - Pej. wilayah Temerloh</option> 
       <option name="8" value="1">PWB - Pej. Wilayah Barat</option> 
       <option name="9" value="1">KOOP - Koperasi LKPP</option> 
       <option name="10" value="1">KSKLKPP - KSK LKPP Negeri Pahang</option>   
       <option name="11" value="1">KSKCIP - KSK LKPP Cawangan Ibu Pejabat</option> 
       <option name="12" value="1">IBUPEJ - IBU PEJABAT</option> 
       <option name="13" value="1">KESATUAN - KESATUAN SEKERJA</option>          
      </select> 
     </div> 
    </div> 

    <div class="form-group row text-left"> 
     <label for="exampleTextarea" class="col-2 col-form-label">Catatan: </label> 
     <div class="col-10"> 
      <textarea class="form-control" id="exampleTextarea" rows="3" name="catatan" id="catatan"></textarea> 
     </div> 
    </div> 

    <center><button type="submit" class="btn btn-info">Submit</button></center>      

</form> 

当我点击提交,没有错误,但数据不插入到数据库中。

回答

1

当你想从表单数据传递给你的PHP脚本,你必须记住,name属性被分配给该数据在PHP脚本找到。

<button type="submit" class="btn btn-info">Submit</button> 

在您的按钮中,您没有分配name属性。因此,在PHP脚本isset($ _ POST ['submit'])中的post方法后没有找到任何提交属性。所以它返回false。

<button type="submit" class="btn btn-info" name="submit" value="submit" >Submit</button> 

所以你必须使用这一行按钮。

1

尝试这样的:

<button type="submit" class="btn btn-info" name="submit" value="submit" >Submit</button> 
1

if (isset($_POST['submit'])) {这是行不通的,为什么,因为你还没有提交按钮的提供者的名称<button type="submit" class="btn btn-info">Submit</button>

添加提交按钮像下面的名字。

<button type="submit" name="submit" class="btn btn-info">Submit</button> 

OR

0

简单的检查,如果$_POST不为空

if(!empty($_POST)) // form has been submitted 

你在你的情况有名字submit没有表单输入

0

嗨给名按钮如下

<center><button type="submit" name="submit" class="btn btn-info">Submit</button></center> 

这将工作

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