2012-04-18 132 views
-1

我读了这么多关于这个话题的文章,我还有一些重要和基本的问题。 如果事务不用于SQL,交易的目的是什么?它在wcf中如何帮助我? 这篇文章显示了使用简单的交易的例子:交易目的

http://msdn.microsoft.com/en-us/library/ms172152(v=vs.90).aspx

这是什么下面的代码,如果它不是用于回滚他们试图挽回的情况下,该代码失败什么都的目的是什么?

void RootMethod() 
{ 
    using(TransactionScope scope = new TransactionScope()) 
    { 
      /* Perform transactional work here */ 
      SomeMethod(); 
      scope.Complete(); 
    } 
} 

void SomeMethod() 
{ 
    using(TransactionScope scope = new TransactionScope()) 
    { 
      /* Perform transactional work here */ 
      scope.Complete(); 
    } 
} 
+1

同交易是其他地方,我想。无论发生什么,或者什么都没有发生。 – cHao 2012-04-18 17:17:14

+0

我已经删除了最后一个问题。请只同时提出一个问题。 – usr 2012-04-18 17:17:37

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@cHao,不正确。仅支持交易的资源参与。 – usr 2012-04-18 17:21:04

回答

2

只有支持事务的资源参与事务。通常,这只是SQL Server。消息队列还支持事务。

如果您不使用任何启用事务的资源(如正常变量...),则这将不会执行任何操作。

0

这里有一个很好的例子

http://msdn.microsoft.com/en-us/library/system.transactions.transactionscope(v=vs.90).aspx#Y500

在该示例中(上面的链接,下面的代码)的SQL的连接对象将自动参与事务 - 因此这些SQL命令将不会前犯交易完成(scope.Complete)。通过这种方式,只有在发生其他事件时,两个服务器才会发生。任何异常都会导致回滚。

你的例子并不清楚,因为它只是在该页面的上下文中描述嵌套的作用域。这个例子展示了一些可以被认为是嵌套的东西,而不是一些会做任何有用的代码。

下面是微软的示例代码,我认为是很清楚的:

// This function takes arguments for 2 connection strings and commands to create a transaction 
// involving two SQL Servers. It returns a value > 0 if the transaction is committed, 0 if the 
// transaction is rolled back. To test this code, you can connect to two different databases 
// on the same server by altering the connection string, or to another 3rd party RDBMS by 
// altering the code in the connection2 code block. 
static public int CreateTransactionScope(
    string connectString1, string connectString2, 
    string commandText1, string commandText2) 
{ 
    // Initialize the return value to zero and create a StringWriter to display results. 
    int returnValue = 0; 
    System.IO.StringWriter writer = new System.IO.StringWriter(); 

    try 
    { 
     // Create the TransactionScope to execute the commands, guaranteeing 
     // that both commands can commit or roll back as a single unit of work. 
     using (TransactionScope scope = new TransactionScope()) 
     { 
      using (SqlConnection connection1 = new SqlConnection(connectString1)) 
      { 
       // Opening the connection automatically enlists it in the 
       // TransactionScope as a lightweight transaction. 
       connection1.Open(); 

       // Create the SqlCommand object and execute the first command. 
       SqlCommand command1 = new SqlCommand(commandText1, connection1); 
       returnValue = command1.ExecuteNonQuery(); 
       writer.WriteLine("Rows to be affected by command1: {0}", returnValue); 

       // If you get here, this means that command1 succeeded. By nesting 
       // the using block for connection2 inside that of connection1, you 
       // conserve server and network resources as connection2 is opened 
       // only when there is a chance that the transaction can commit. 
       using (SqlConnection connection2 = new SqlConnection(connectString2)) 
       { 
        // The transaction is escalated to a full distributed 
        // transaction when connection2 is opened. 
        connection2.Open(); 

        // Execute the second command in the second database. 
        returnValue = 0; 
        SqlCommand command2 = new SqlCommand(commandText2, connection2); 
        returnValue = command2.ExecuteNonQuery(); 
        writer.WriteLine("Rows to be affected by command2: {0}", returnValue); 
       } 
      } 

      // The Complete method commits the transaction. If an exception has been thrown, 
      // Complete is not called and the transaction is rolled back. 
      scope.Complete(); 

     } 

    } 
    catch (TransactionAbortedException ex) 
    { 
     writer.WriteLine("TransactionAbortedException Message: {0}", ex.Message); 
    } 
    catch (ApplicationException ex) 
    { 
     writer.WriteLine("ApplicationException Message: {0}", ex.Message); 
    } 

    // Display messages. 
    Console.WriteLine(writer.ToString()); 

    return returnValue; 
} 
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为什么在上面的例子中,后面的Connection,Connection2在Connection1的初始化中初始化?它是重要的还是可以在Connection1的初始化之外完成? – 2012-04-19 12:18:01

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任何人都想要anser? – 2012-04-19 22:07:00

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它在评论中就在那里 - 你节省了资源,因为如果connection1可以连接和工作,你只需要打开connection2,否则你最终会回滚。阅读评论 – Hogan 2012-04-20 14:50:12