我试图用React Native项目上的不同屏幕进行练习。这里是我的代码从App.js文件。反应本机不变违规:查看配置
/**
* Sample React Native App
* https://github.com/facebook/react-native
* @flow
*/
import React, { Component } from 'react';
import {
Platform,
StyleSheet,
Text,
View
} from 'react-native';
import { StackNavigator } from 'react-navigation';
class HomeScreen extends React.Component {
static navigationOptions = {
title: "welcome",
};
render() {
return <Text style={{ color: 'black '}}>Hello, Navigation!</Text>;
}
}
const navigation = StackNavigator({
Home: { screen: HomeScreen },
});
export default class App extends Component<{}> {
render() {
return <navigation/>;
}
}
const styles = StyleSheet.create({
container: {
flex: 1,
justifyContent: 'center',
alignItems: 'center',
backgroundColor: '#fff',
},
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>
当我运行反应原生运行Android的,我得到一个不变冲突,它告诉我“来查看未找到的配置或名称导航”。然后发生这种违规行为的所有网站。 请帮助谢谢
你在代码中包含的那些脚本是什么? – alexdriedger
Stack Overlfow做到了,我不知道 –