蟒蛇解析text/plain的电子邮件

假设我有一个看起来像这样的电子邮件：蟒蛇解析text/plain的电子邮件

From hostname Tue Jun 15 21:43:30 2010 
Received: (qmail 8580 invoked from network); 15 Jun 2010 21:43:22 -0400 
Received: from mail-fx0-f44.google.com (209.85.161.44) 
by ip-73-187-35-131.ip.secureserver.net with SMTP; 15 Jun 2010 21:43:22 -0400 
Received: by fxm19 with SMTP id 19so170709fxm.3 
for <[email protected]>; Tue, 15 Jun 2010 18:47:33 -0700 (PDT) 
MIME-Version: 1.0 
Received: by 10.103.84.1 with SMTP id m1mr2774225mul.26.1276652853684; Tue, 15 
Jun 2010 18:47:33 -0700 (PDT) 
Received: by 10.123.143.4 with HTTP; Tue, 15 Jun 2010 18:47:33 -0700 (PDT) 
Date: Tue, 15 Jun 2010 20:47:33 -0500 
Message-ID: <[email protected]> 
Subject: TEST 12 
From: Full Name <[email protected]> 
To: [email protected] 
Content-Type: text/plain; charset=ISO-8859-1 

ONE 
TWO 
THREE

我知道我可以使用msg = email.message_from_string(str)和msg['To']得到[email protected]，但如何鉴别“一二三“ 在底部？奖励！如何识别顶部的所有“已收到：”k/v对？当我尝试：

msg['Received']

我只得到第一个。我如何获得第二个？

来源

2016-11-12 Jason Michael

这只能解决“奖励”：您可以使用msg.get_all('Received')。

>>> msg.get_all('Received') 
['(qmail 8580 invoked from network); 15 Jun 2010 21:43:22 -0400', 'from mail-fx0-f44.google.com (209.85.161.44)'] 
>>> msg.get_all('Received')[1] 
'from mail-fx0-f44.google.com (209.85.161.44)'

侧面说明，你可以探索在解释dir(msg)和help(msg)。

来源

2016-11-12 21:20:50 Aaron

upvoted用于教学如何使用help（）和dir（），这是我在其他语言中使用的令人难以置信的有用函数。 –

我可以找出“一二三”从电子邮件的正文中使用此代码：

msg.get_payload()

Yaah我！

来源

2016-11-14 04:18:55

蟒蛇解析text/plain的电子邮件

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