1
我试图删除图像框与阿贾克斯,我class="box"
不消失,当我点击删除,但我的形象已经从数据库中删除,并从文件夹中取消链接,任何人都可以看到,如果有些事情错我的代码,在此先感谢!成功功能不起作用
我的代码:
<ul>
<?php while ($result = mysql_fetch_array($sql)) { ?>
<li class="box">
<div class="image-box">
<div class="items-image" style="background-image: url(upload/<?php echo $result['img_1']; ?>);"></div>
<p class="error" style="display: none;">Can't delete</p>
<div class="items-footer">
<a class="delete" id="<?php echo $result['img_id']; ?>"><i class="fa fa-trash fa-lg"></i></a>
</div>
</div>
</li>
<?php } ?>
</ul>
$(document).ready(function(){
$(".delete").on('click', function(evt){
var del_id = $(this).attr('id');
var prop_id = "<?php echo $ID; ?>";
$.ajax({
type:'POST',
url:'image_delete.php',
data: ({delete_id : del_id, product_id: prop_id}),
success: function(data) {
if(data == '0') {
$(".error").show();
} else if(data == '1') {
$(this).parents(".box").animate({ backgroundColor: "#003" }, "slow").animate({ opacity: "hide" }, "slow");
}
}
});
});
});
image_upload.php
<?php
include 'connect.php';
$path = "upload/";
if(isset($_POST['delete_id'])){
$delete_id = $_POST['delete_id'];
$product_id = $_POST['product_id'];
$check = mysql_query("SELECT COUNT(img_id) as cnt FROM fm_product_image WHERE p_id_img = '$product_id'") or die(mysql_error());
$getcheck = mysql_fetch_array($check);
if($getcheck['cnt'] == '1') {
echo '0';
} else {
$sql = mysql_query("SELECT img_1 FROM fm_product_image WHERE img_id = '$delete_id'") or die(mysql_error());
$result = mysql_fetch_array($sql);
$delete = $result['img_1'];
$unlink = $path.$delete;
if (unlink($unlink)) {
mysql_query("DELETE fm_product_image FROM fm_product_image WHERE img_id = '$delete_id'") or die(mysql_error());
echo '1';
} else {
echo '0';
}
}
}
?>
还是做esn't工作 –
错字'VAR盒= .closest( “箱子”);' – roullie
exacly什么不起作用? – madalinivascu