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我是一个初学者,我想提出一个PHP邮件形式那样:PHP邮件形式:邮件是空白
但它不工作,我收到邮件但在任何东西,我不明白为什么:/
这里是我的表单的HTML代码:
<form method=POST action=formmail.php >
<input type=hidden name=subject value=formmail>
<p>Pseudo* :<br>
<span class="padding1"><input type="text" name="your-name" value="" size="40" aria-required="true" aria-invalid="false"></span> </p>
<p>Email* :<br>
<span class="your-email padding1"><input type="email" name="your-email" value="" size="40" aria-required="true" aria-invalid="false"></span> </p>
<p>Link of the GIF* :<br>
<span class="link-url padding1"><input type="url" name="link-url" value="" aria-invalid="false"></span> </p>
<p><input type="submit" value="Send"><img class="ajax-loader" src="http://s584101063.onlinehome.fr/wp-content/plugins/contact-form-7/images/ajax-loader.gif" alt="Envoi en cours ..." style="visibility: hidden;"></p>
</div>
</form>
这里是我的PHP代码:
<?php
$TO = "[email protected]";
$h = "From: " . $TO;
$message = "";
while (list($key, $val) = each($HTTP_POST_VARS)) {
$message .= "$key : $val\n";
}
mail($TO, $subject, $message, $h);
Header("Location: http://gifmyday.com/index.html");
?>
而(名单($键,$ VAL)=每($ HTTP_POST_VARS))这部分是种呸的,这是什么$ HTTP_POST_VARS - 它不是只使用上述代码中设置。 Id建议做foreach($ HTTP_POST_VARS作为$ key => $ value)而不是 – ArtisticPhoenix
您的CSS代码是php – progsource
progsource:羞耻对我我很累,我修改了, – alexandresecanove