我建立一个非常简单的服务,应该返回一棵树一样通过递归情况下,类中定义的结构:上运行时编码的递归数据结构为JSON与瑟茜http4s
case class Node(id: Int, name: String, children: Seq[Node] = Seq())
但由于某些原因,我一直得到一个以下编译错误:
Error:(24, 70) could not find implicit value for parameter encoder: io.circe.Encoder[Seq[com.ansarada.ds.docviewer.server.Main.Node]]
implicit val nodesEncoder: EntityEncoder[Seq[Node]] = jsonEncoderOf[Seq[Node]]Error:(24, 70) not enough arguments for method jsonEncoderOf: (implicit encoder: io.circe.Encoder[Seq[com.ansarada.ds.docviewer.server.Main.Node]])org.http4s.EntityEncoder[Seq[com.ansarada.ds.docviewer.server.Main.Node]]. Unspecified value parameter encoder. implicit val nodesEncoder: EntityEncoder[Seq[Node]] = jsonEncoderOf[Seq[Node]]
的代码被编译,一旦我删除儿童元素定义,把一个节点到平面物体:
case class Node(id: Int, name: String)
任何人都可以帮助我定义正确的Json编码器的情况下嵌套的孩子?
全码:
import org.http4s.circe._
import org.http4s.dsl._
import org.http4s.server.blaze.BlazeBuilder
import org.http4s.server.{Server, ServerApp}
import org.http4s.{EntityEncoder, HttpService}
import scalaz.concurrent.Task
object Main extends ServerApp {
import io.circe.generic.auto._
import io.circe.syntax._
case class Node(id: Int, name: String, children: Seq[Node] = Seq())
def getNodes: Seq[Node] = Seq(
Node(0, "#One"),
Node(1, "#Two"),
Node(2, "#Three")
)
implicit val nodeEncoder: EntityEncoder[Node] = jsonEncoderOf[Node]
implicit val nodesEncoder: EntityEncoder[Seq[Node]] = jsonEncoderOf[Seq[Node]]
override def server(args: List[String]): Task[Server] = {
val nodesService = HttpService {
case _ @ GET -> Root/"nodes" =>
Ok(getNodes.asJson)
}
BlazeBuilder
.bindHttp(8080, "localhost")
.mountService(nodesService, "/api")
.start
}
}