-1
我试图通过使用json_encode我想从PHP通过json_encode成JavaScript
从PHP传递数组转换成JavaScript,但是当我提醒值,我只看到“Object对象等”
当我它的var_dump我看到实际的阵列,但它不是显示他们在警报
任何帮助,将不胜感激
问候
这是后续代码var_dump
array(1) {
[0]=>
array(2) {
["id"]=>
string(19) "3.0268"
["postcode"]=>
string(137) "hello"
}
}
array(2) {
[0]=>
array(2) {
["id"]=>
string(19) "3.0268070455319E+17"
["postcode"]=>
string(137) "ECMWF continues its flip-flopping, still a temp drop next week & #snow risk but then no rise, http://t.co/tBlg9Ihs #ukweather #uksnow"
} 代码
<?php
$con = mysql_connect('localhost', 'root', '');
mysql_select_db('test');
$result = mysql_query("SELECT * FROM address");
$arr = array();
while($row = mysql_fetch_assoc($result)) {
$arr[] = $row;
}
?>
<script>
var test = <?php echo json_encode($arr); ?>;
alert(test);
</script>
什么是打印输出? – Mathletics 2013-02-22 19:39:19
这是预期的输出。一切安好。对象的*默认字符串表示*是'“[object Object]”。使用'console.log'来检查变量。 – 2013-02-22 19:40:37
看到这个:http://stackoverflow.com/questions/684672/loop-through-javascript-object – 2013-02-22 19:41:25