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我有一个集合,我想要聚合,使特定的字段不同,但也将其他字段数据添加到该聚集的结果。下面是将一些数据添加到不同的查询中mongodb
{
"_id": ObjectId("57d6bc99e4b014fc13cf9579"),
"_class": "hbservlet.FinalSubmissions",
"active": true,
"mappedTracks":
[
{ "position": 0, "title": "01. Ain't No Time.mp3", "url": "/published/music/tr157d6bc99e4b014fc13cf9579_.aac" },
{ "position": 1, "title": "02. In Her Mouth.mp3", "url": "/published/music/tr257d6bc99e4b014fc13cf9579_.aac" },
{ "position": 2, "title": "03. Maybach.mp3", "url": "/published/music/tr357d6bc99e4b014fc13cf9579_.aac" }
],
"createdBy": ObjectId("57d6bb99b17ee01a5427af08"),
"userId": ObjectId("57d6bb99b17ee01a5427af08"),
"artistname": "test",
}, {
"_id": ObjectId("14d6bc99ebc942fc13cf9579"),
"_class": "hbservlet.FinalSubmissions",
"active": false,
"mappedTracks": [
{ "position": 0, "title": "partysong.mp3", "url": "/published/music/tr114d6bc99ebc942fc13cf9579_.aac" },
{ "position": 1, "title": "outside", "url": "/published/music/tr214d6bc99ebc942fc13cf9579_.aac" },],
"createdBy": ObjectId("57d6bb99b17ee01a5427af08"),
"userId": ObjectId("57d6bb99b17ee01a5427af08"),
"artistname": "mynameismyname",
}
我用的是不同的查询(db.published.distinct(“mappedTracks”))来收集我收藏的一个例子所有mappedTracks,所以我得到这个
{ "position": 0, "title": "01. Ain't No Time.mp3", "url": "/published/music/tr157d6bc99e4b014fc13cf9579_.aac" },
{ "position": 1, "title": "02. In Her Mouth.mp3", "url": "/published/music/tr257d6bc99e4b014fc13cf9579_.aac" },
{ "position": 2, "title": "03. Maybach.mp3", "url": "/published/music/tr357d6bc99e4b014fc13cf9579_.aac" },
{ "position": 0, "title": "partysong.mp3", "url": "/published/music/tr114d6bc99ebc942fc13cf9579_.aac" },
{ "position": 1, "title": "outside", "url": "/published/music/tr214d6bc99ebc942fc13cf9579_.aac" }
这是我想要的结果,但我也想添加它所属的文档的_id,userID,artistname到创建的新对象。
谢谢婉,这指出我的方向是正确的。我正在重新考虑我的文档结构以获得更高效的系统。 –