复杂的搜索SQL查询

Question

我需要你的帮助与SQL查询。

我需要在该mathing元素具有smalest顺序表中选择值，目前我有以下查询：

SELECT p.confirmation, 
    p.lname, 
    p.fname, 
    p.profiletype, 
    a.address1, 
    a.city, 
    c.contactinfo 
FROM profile p 
LEFT JOIN contact c 
    ON p.confirmation = c.profileid 
    AND c.ord = 1 
LEFT JOIN address a 
    ON p.confirmation = a.profileid 
    AND a.ord =1 

这项工作做得很好，当smalest“a.ord”或c.ord “是1，但最小值不会永远是一个，也可能是其他任何数字，所以我试着不更迭如下：

SELECT p.confirmation, 
    p.lname, 
    p.fname, 
    p.profiletype, 
    a.address1, 
    a.city, 
    c.contactinfo 
FROM profile p 
LEFT JOIN contact c 
    ON p.confirmation = c.profileid 
    min(c.ord) 
LEFT JOIN address a 
    ON p.confirmation = a.profileid 
    min(a.ord) 

我已经取代” AND a.ord = 1 “by”min（a.ord）“没有成功。

我怎么能做到这一点，没有做出两个单独的查询。

有没有一种方法，我可以在排序的

SELECT c.ord FROM contact c WHERE p.confirmation = c.profileid ORDER BY c.ord LIMIT 1 

当前SQL里面添加的东西？

谢谢！

Answer 1

AND a.ord =1 // if a.cord is always 1 
    AND a.ord <=1 // if a.cord is always <1 (eg. .9 or .75) 
    // or just leave it.. i dont know your script, but is it needed? 
    // same at c.cord! 
    // but rather use where! see below 

而且作为一个例子：

SELECT 
    p.confirmation, 
    p.lname, 
    p.fname, 
    p.profiletype, 
    a.address1, 
    a.city, 
    c.contactinfo 
FROM 
    profile AS p 
LEFT JOIN 
    contact AS c 
ON 
    p.confirmation=c.profileid 
LEFT JOIN 
    address AS a 
ON 
    p.confirmation=a.profileid 
WHERE 
    c.ord=1 AND a.ord=1 
ORDER BY 
    c.ord ASC, a.ord ASC 

希望我得到了你的问题所在

Answer 2

您可以通过计算分ORD为每个表，然后使用，在加入做：

SELECT p.confirmation, p.lname, p.fname, p.profiletype, 
     a.address1, a.city, c.contactinfo 
FROM profile p LEFT JOIN 
    (select c.profileid, MIN(c.ord) as minord 
     from contact c 
     group by c.profileid 
    ) minco 
    on minco.profileid = c.profileid left join 
    contact c 
    ON p.confirmation = c.profileid and minco.minord = c.ord LEFT JOIN 
    (select a.profileid, min(a.ord) as minord 
     from address a 
     group by a.profileid 
    ) minao 
    on minao.profileid = c.profileid left join 
    address a 
    ON p.confirmation = a.profileid and minao.minord = a.ord 

Answer 3

只需在MySQL中使用LIMIT 1即可在订购后获得第一行：

SELECT p.confirmation, 
    p.lname, 
    p.fname, 
    p.profiletype, 
    a.address1, 
    a.city, 
    c.contactinfo 
FROM profile p 
LEFT JOIN contact c 
    ON p.confirmation = c.profileid 
LEFT JOIN address a 
    ON p.confirmation = a.profileid 
ORDER BY c.ord, a.ord 
LIMIT 1 

Answer 4

这样的事情可能就是你要找的东西。您可以根据所需的优先级将ORDER BY c.ord ASC, a.ord ASC更改为ORDER BY a.ord ASC, c.ord ASC。

SELECT p.confirmation, 
    p.lname, 
    p.fname, 
    p.profiletype, 
    a.address1, 
    a.city, 
    c.contactinfo 
FROM profile p 
LEFT JOIN contact c 
    ON p.confirmation = c.profileid 
LEFT JOIN address a 
    ON p.confirmation = a.profileid 
ORDER BY c.ord ASC, a.ord ASC 
LIMIT 1 

Answer 5

更新：

我finalyl解决我的问题与嵌套SELECT：

SELECT p.confirmation, 
     p.lname, 
     p.fname, 
     p.profiletype, 
     a.address1, 
     a.city, 
     c.contactinfo 
    FROM profile p 
    LEFT JOIN contact c 
     ON p.confirmation = c.profileid 
     AND c.ord=(SELECT ord FROM contact WHERE profileid= p.confirmation ORDER BY ord LIMIT 1) 
    LEFT JOIN address a 
     ON p.confirmation = a.profileid 
     AND a.ord=(SELECT ord FROM address WHERE profileid= p.confirmation ORDER BY ord LIMIT 1) 

谢谢#Gordon Linoff您的洞察力上使用一个查询的多个选择！