Escape不能使用可选参数！

Question

在我使用LIKE运算符的可选参数查询中，Escape特殊字符不起作用。 这是查询

NAME LIKE CASE WHEN '%'+@Name+'%' IS NULL THEN NAME ELSE '%'+@Name+'%' END 

的一部分，我想我可以把它像

NAME LIKE CASE WHEN '%'+@Name+'%'ESCAPE '\' IS NULL THEN NAME ELSE '%'+@Name+'%' END 

但是当我添加逃逸“\”，但它引发错误。 任何帮助？

演示代码：

set @Name='Restaur\[ant' 

     SELECT  [JOB].HOUSE_CODE, [JOB].JOB_CODE, [JOB].OPEN_DATE, [JOB].NAME AS Position, [JOB].DESCRIPTION, [RESTAURANT].ZIP_CODE AS ZipCode, 
          [STATE].STATE_NAME AS State, [RESTAURANT].CITY_NAME AS City 
    FROM   [JOB] INNER JOIN 
          [RESTAURANT] ON [JOB].HOUSE_CODE = [RESTAURANT].HOUSE_CODE INNER JOIN 
          [STATE] ON [RESTAURANT].STATE_CODE = [STATE].STATE_CODE INNER JOIN 
          [JOB_CODE] ON [JOB].HOUSE_CODE = [JOB_CODE].HOUSE_CODE AND [JOB].JOB_CODE = [JOB_CODE].JOB_CODE AND 
          [RESTAURANT].HOUSE_CODE = [JOB_CODE].HOUSE_CODE 
    WHERE  ( [JOB].NAME LIKE CASE WHEN '%'+@Name+'%' IS NULL THEN [JOB].NAME ELSE '%'+@Name+'%' END ESCAPE '\') 

Answer 1

你在寻找它呢？我想你的第一个例子，它的表现我希望它的方式：如果我提供一个价值@Name它只是如果我离开它，它会返回所有名称返回一个包含该值名称，

CREATE TABLE test2 (
NAME varchar(100) 
) 

GO 

INSERT test2(name) values('Fred') 
INSERT test2(name) values('bert') 

GO 
DECLARE @name VARCHAR(100) 
--SET @name='re' 
SELECT * FROM test2 
WHERE NAME LIKE CASE WHEN '%'+@Name+'%' IS NULL THEN NAME ELSE '%'+@Name+'%' END 

？

Answer 2

你真的想比较'％'+ @名称+'％ESCAPE'\'为空吗？我想你想要把逃生关键字以后，像这样：

CASE WHEN '%'+@Name+'%' IS NULL THEN NAME ELSE '%'+@Name+'%' ESCAPE '\' END 

Answer 3

你试图把一个空间ESCAPE过吗？

+'%'ESCAPE '\' IS 

这样：

+'%' ESCAPE '\' IS 

Answer 4

把ESCAPE CASE语句之外。此外，仅为NULL测试@Name就足够了。

NAME LIKE CASE WHEN @Name IS NULL THEN NAME ELSE '%'+@Name+'%' END ESCAPE `\` 

编辑：下面是一些演示代码来说明该技术。

declare @test table (
    name varchar(100) 
) 

insert into @test 
    (name) 
    select 'I am 100% confident this works.' union all 
    select 'There can be no doubt.' union all 
    select 'I would like to eat in fine restaur[ant some day.' 

declare @name varchar(100) 

/* Case when @name is NULL */ 
select name 
    from @test 
    where name like case when @name is null then name else '%'+@name+'%' end escape '\' 

set @name = '100\%' 

/* Case when @name has a value with a % */ 
select name 
    from @test 
    where name like case when @name is null then name else '%'+@name+'%' end escape '\' 

set @name = 'restaur\[ant' 

/* Case when @name has a value with a [ */ 
select name 
    from @test 
    where name like case when @name is null then name else '%'+@name+'%' end escape '\'