我有一个年份对象。现在让我们说只有两年,其获得者和制定者从我的DTO创建一个列表
private String mYearOne;
private String mYearTwo;
public String getmYearOne() {
return mYearOne; }
public void setmYearOne(String mYearOne) {
this.mYearOne = mYearOne; }
public String getmYearTwo() {
return mYearTwo; }
public void setmYearTwo(String mYearTwo) {
this.mYearTwo = mYearTwo; }
然后,每年有三个保险计划。它的获得者和制定者。
private String healthPlan;
private String carPlan;
private String housePlan;
private String healthPlanTwo;
private String carPlanTwo;
private String housePlanTwo;
public String getHealthPlan() {
return healthPlan; }
public void setHealthPlan(String healthPlan) {
this.healthPlan = healthPlan; }
public String getCarPlan() {
return carPlan; }
public void setCarPlan(String carPlan) {
this.carPlan = carPlan; }
public String getHousePlan() {
return housePlan; }
public void setHousePlan(String housePlan) {
this.housePlan = housePlan; }
public String getHealthPlan() { //For the second year
return healthPlan; }
public void setHealthPlan(String healthPlan) {
this.healthPlan = healthPlan; }
public String getCarPlan() {
return carPlan; }
public void setCarPlan(String carPlan) {
this.carPlan = carPlan; }
public String getHousePlan() {
return housePlan; }
public void setHousePlan(String housePlan) {
this.housePlan = housePlan; }
public String getHealthPlanTwo() {
return healthPlanTwo; }
public void setHealthPlanTwo(String healthPlanTwo) {
this.healthPlanTwo = healthPlanTwo; }
public String getCarPlanTwo() {
return carPlanTwo; }
public void setCarPlanTwo(String carPlanTwo) {
this.carPlanTwo = carPlanTwo; }
public String getHousePlanTwo() {
return housePlanTwo; }
public void setHousePlanTwo(String housePlanTwo) {
this.housePlanTwo = housePlanTwo; }
您会注意到代码很笨重。我需要在一年的<list>
中定义它们。因此,如果考虑10年,我将分别乘以3 = 30计划和其获得者和设定者10乘以 。
这怎么办?
在你的例子中,void方法如何返回类型? – 2011-12-28 08:54:22
hehe ..对不起..这是我忽略的一个错误..感谢您提出! – Neo 2011-12-28 16:10:15