链接jQuery的菜单按钮，网址

Question

我有这样的jQuery的菜单脚本：

<script type="text/javascript"> 
     jQuery(document).ready(function(){ 


      jQuery('#promo').pieMenu({icon : [ 
        { 
         path : "/wp-content/themes/Tersus/images/piemenu/winamp.png", 
         alt : "Winamp", 
         fn : function(){alert('Click:: Find');return false} 
        }, { 
         path : "/wp-content/themes/Tersus/images/piemenu/vlc.png", 
         alt : "VLC Media Player", 
         fn : function(){alert('Click:: Plus');return false} 
        },{ 
         path : "/wp-content/themes/Tersus/images/piemenu/QuickTime.png", 
         alt : "Quick Time Player", 
         fn : function(){alert('Click:: Home');return false} 
        },{ 
         path : "/wp-content/themes/Tersus/images/piemenu/WMP.png", 
         alt : "Windows Media Player", 
         fn : function(){alert('Click:: Music');return false} 
        },{ 
         path : "/wp-content/themes/Tersus/images/piemenu/popup.png", 
         alt : "נגן Popup", 
         fn : function(){alert('Click: E-Mail');return false} 
        },{ 
         path : "/wp-content/themes/Tersus/images/piemenu/iTunes.png", 
         alt : "iTunes", 
         fn : function(){alert('Click: Config');return false} 

      }); 
     }) 
    </script> 
         },{ 

我需要点击时的图标链接到外部URL，我怎么能做到这一点？

和我在写这行，因为它需要一个更好的代码的解释，因为代码很长......（？）

Answer 1

function(){  
    window.location.href = 'http://domain.com/'; 
    return false 
}