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我在执行一个RNN,反之到我发现其例子最小化仅在最后步骤中的为输出成本如何在TensorFlow上乘以单张量的张量列表?
x = tf.placeholder ("float", [features_dimension, None, n_timesteps])
y = tf.placeholder ("float", [labels_dimension, None, n_timesteps])
# Define weights
weights = {'out': tf.Variable (tf.random_normal ([N_HIDDEN, labels_dimension]))}
biases = {'out': tf.Variable (tf.random_normal ([labels_dimension]))}
def RNN (x, weights, biases):
# Prepare data shape to match `rnn` function requirements
# Current data input shape: (features_dimension, BATCH_SIZE, n_timesteps)
# Required shape: `n_timesteps` tensors list of shape (BATCH_SIZE, features_dimension)
# We make a division of the data to split it in individual vectors that
# will be fed for each timestep
# Permuting features_dimension and n_timesteps
# Shape will be (n_timesteps, BATCH_SIZE, features_dimension)
x = tf.transpose (x, [2, 1, 0])
# Reshaping to (BATCH_SIZE*n_timesteps, features_dimension) (we are removing the depth dimension with this)
x = tf.reshape(x, [BATCH_SIZE*n_timesteps, features_dimension])
# Split the previous 2D tensor to get a list of `n_timesteps` tensors of
# shape (batch_size, features_dimension).
x = tf.split (x, n_timesteps, 0)
# Define a lstm cell with tensorflow
lstm_cell = rnn.BasicLSTMCell (N_HIDDEN, forget_bias=1.0)
# Get lstm cell output
outputs, states = rnn.static_rnn (lstm_cell, x, dtype=tf.float32)
# Linear activation; outputs contains the array of outputs for all the
# timesteps
pred = tf.matmul (outputs, weights['out']) + biases['out']
然而,对象outputs
是Tensor
与n_timesteps
元素的列表,所以pred = tf.matmul (outputs, weights['out']) + biases['out']
抛出错误
ValueError: Shape must be rank 2 but is rank 3 for 'MatMul' (op: 'MatMul') with input shapes: [100,128,16], [16,1].
。我怎样才能做这个乘法?