2012-03-22 87 views
0

我正在使用jQuery在代码中的.ascx控件的方法的AJAX调用后面获取业务对象的列表:jQuery的阿贾克斯ASP.NET .ASCX控制

C#代码:

if (Request.Headers["X-OFFICIAL-REQUEST"] == "TRUE") ReturnList(Request.Params[1]); 

    protected void ReturnList(string param) 
    { 
    Response.Write(GetBusinesses(param)); 
    Response.Flush(); 
    try { 
     Response.Close(); 
     } 
    catch { } 
    Response.End(); 
    return; 
    } 

private string GetBusinesses(string classificationName) 
{ 
    System.Web.Script.Serialization.JavaScriptSerializer jSearializer = null; 
    if (!string.IsNullOrEmpty(classificationName)) 
    { 
     dSourse = BusinessesDBService.Instance.GetLatestListingsUpdates(classificationName).ToList(); 
     jSearializer = new System.Web.Script.Serialization.JavaScriptSerializer(); 
    } 
    return jSearializer.Serialize(dSourse); 

} 

jQuery代码:

window.jQuery.ajax({ 
    type: "POST", 
    async: false, 
    url: location.href, 
    dataType: "json", 
    data: ({ 'FUNCTION': 'ReturnList', 'param0': classificationName.toLowerCase() }), 
    success: function (data) { 
     data = eval(data); 

    }, 
    error: function (XMLHttpRequest, textStatus, errorThrown) { 
    }, 
    beforeSend: function (xhr) { 
     xhr.setRequestHeader("X-OFFICIAL-REQUEST", "TRUE"); //Used to ID as a AJAX Request 
    }, 
    complete: function (XMLHttpRequest, textStatus) { 
    //build HTML 
     var tablestring = '<table ><tr><td>UsreID" + "</td><td>UserName</td></tr>'; 

     for (var i = 0, len = data.length; i < len; ++i) { 
      tablestring = tablestring + "<tr>"; 
      tablestring = tablestring + "<td>" + 
       data[i].BusinessID + "</td>"; 
      tablestring = tablestring + "<td>" + 
       data[i].BusinessName + "</td>"; 
      tablestring = tablestring + "</tr>"; 
     } 
     tablestring = tablestring + "</table>"; 
     var divResult = document.getElementById("divAjax"); 
     divResult.innerHTML = tablestring; 

    } 
}); 

HTTP调用执行罚款和收集是斯里alize并返回响应,但我在这里有一些问题。主要的是没有创建HTML - 我无法捕获返回的字符串。下面的字符串在呼叫完成后显示在Firebug脚本窗口中

[{“BusinessID”:6549,“BusinessName”:“Ivory Store”,“IsMain”:true},{“BusinessID”:16565, “BusinessName”:“Classic Nails”,“IsMain”},{“BusinessID”:5877,“BusinessName”:“Visible Changes Hair”,“IsMain”:true}]

同样在Firebug中, XMLHttpRequest响应对象中的字符串和错误消息是“JSON无效”任何suggetions?非常感谢你。

+0

如果你有无效的JSON麻烦,无法找到问题,我建议你使用像[JSONLint]一个验证器(http://jsonlint.com/)。 – 2012-03-22 21:14:13

回答

-1

出于某种原因,下面的代码隐藏的C#解析器代码没有将“]”附加到字符串的末尾,所以我不得不手动追加它 - 它的工作!谢谢。

public static string Serialize<T>(T obj) 
    { 
     DataContractJsonSerializer serializer = new DataContractJsonSerializer(obj.GetType()); 
     MemoryStream ms = new MemoryStream(); 
     serializer.WriteObject(ms, obj); 
     string retVal = Encoding.UTF8.GetString(ms.ToArray()); 
     return retVal + "]"; 
    } 
+1

尝试“冲洗” MemoryStream。如果它实际上并没有附加尾部']',这将是框架中的一个重大缺陷,并且其他几个人也会遇到类似的问题。 – 2012-03-26 18:33:41

1

无效JSON

[{"BusinessID":6549,"BusinessName":"Ivory Store","IsMain":true}, {"BusinessID":16565,"BusinessName":"Classic Nails","IsMain"},{"BusinessID":5877,"BusinessName":"Visible Changes Hair","IsMain":true}] 

看到在中间的 “IsMain” 可能需要或者

[{"BusinessID":6549,"BusinessName":"Ivory Store","IsMain":true}, {"BusinessID":16565,"BusinessName":"Classic Nails","IsMain":true},{"BusinessID":5877,"BusinessName":"Visible Changes Hair","IsMain":true}] 

OR

[{"BusinessID":6549,"BusinessName":"Ivory Store","IsMain":true}, {"BusinessID":16565,"BusinessName":"Classic Nails","IsMain":false},{"BusinessID":5877,"BusinessName":"Visible Changes Hair","IsMain":true}] 

看到这个页面的缺失部分:点击JSLint的按钮:http://jsfiddle.net/QmMdC/

+0

我的不好,IsMain上的“缺失部分”没问题,当截断实际的JSON时,我失去了“真正的”部分 - 约30个字段。我明天会发布整个对象的JSON。谢谢。 – itisinteresting 2012-03-22 22:41:51

+0

出于某种原因,下面的代码隐藏C#解析器代码没有将“]”追加到字符串的末尾,所以我不得不手动追加它 - 它的工作!谢谢。公共静态字符串序列化(T OBJ) { DataContractJsonSerializer串行=新DataContractJsonSerializer(obj.GetType()); MemoryStream ms = new MemoryStream(); serializer.WriteObject(ms,obj); string retVal = Encoding.UTF8.GetString(ms.ToArray()); return retVal +“]”; } – itisinteresting 2012-03-26 18:22:15

+0

是的,我看到你的C#代码,它是definatly不是我做的方式,在上课,让框架处理序列的该类似乎是做这个的方式.. – 2012-03-27 11:42:57