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我正在一个错误的工作条款:
消息:SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '%'Chinese'%) ORDER BY
text_id DESC LIMIT 10' at line 2
凡与Zend_Db的并不如预期
造成这行代码
$select = $this->_db->select('')
->from(array('t'=>'as_text'))
->where('`s`.`name` LIKE %?%',$search) //this is causing error
->limit((int)$limit)
->order('text_id DESC')
->join(array('s'=>'as_source'),'t.source_id = s.source_id',array('s.name as source'));
我的目标是这样的SQL:
SELECT `t` . * , `s`.`name` AS `source`
FROM `as_text` AS `t`
INNER JOIN `as_source` AS `s` ON t.source_id = s.source_id
WHERE `s`.`name` LIKE '%Chinese%'
ORDER BY `text_id` DESC
LIMIT 10
我认为这是 - >在哪里位,因为w母鸡我删除它,我得到10行。
不,我没做过,但做完后仍然出现错误'SQLSTATE [42000]:语法错误或访问冲突:1064您的SQL语法错误;检查与您的MySQL服务器版本相对应的手册,以在'%'中文'%'附近使用正确的语法'ORDER BY'text_id'在第2行DESC LIMIT 10' – Moak 2010-08-09 04:52:38
我试过了,它会生成一个函数查询, 。问题是WHERE子句应该看起来像这样:WHERE s.name LIKE'%blah%' – user387302 2010-08-09 05:02:11