2009-10-04 53 views

回答

7

one post in the boost mailing list别人看起来像这样做(复制,格式化,服务号码换了,没有别的):

namespace bai = boost::asio::ip; 
bai::tcp::endpoint ep(bai::address_v4(0xD155AB64), 0); // 209.85.171.100:0 
boost::asio::io_service ios; 
bai::tcp::resolver resolver(ios); 
bai::tcp::resolver::iterator iter = resolver.resolve(ep); 
bai::tcp::resolver::iterator end; 
while (iter != end) 
{ 
    std::cerr << (*iter).host_name() << std::endl; // cg-in-f100.google.com 
    ++iter; 
} 

正如你正确地说,这里服务仍然传入,但步通过Boost.Asio的代码揭示了这个(在resolver_service.hpp,我使用的是比较旧的版本1.36):

// First try resolving with the service name. If that fails try resolving 
// but allow the service to be returned as a number. 

所以,只要去0,它应该做你想要什么。

+0

不是你使用端口号“ep(bai :: address_v4(0xD155AB64),80); // 209.85.171.100:80” – Artyom 2009-10-04 20:21:31

+0

我稍微修改了一下这个例子,希望它有帮助。 – gimpf 2009-10-05 12:10:52