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我在Excel/VBA中编写了一个发票工具。调用的对象已从其客户端断开连接 - VBA- SQL查询
当我尝试运行下面的代码(在Excel中)时出现错误消息,我不知道为什么?
错误消息:调用的对象已与其客户端断开连接。
usfOKNAR01.txtfakt4.Value是一个组合框,我从中获取发票的ID。
----从Access数据库运行查询的VBA代码。
Public Sub faktury2()
SQL = ""
SQL = Array("SELECT * FROM [pokaz_Raty] WHERE ID = " & usfOKNAR01.txtfakt4.Value & ";", _
"SELECT DISTINCT(tbINCOME.[Faktura_ID]), tbRATY.[Faktura_ID] FROM tbRATY INNER JOIN tbINCOME ON tbRATY.[Faktura_ID] = tbINCOME.Identyfikator;")
For i = 0 To 1
Set rs = New ADODB.Recordset
rs.Open SQL(i), db, adOpenStatic, adLockReadOnly 'here the error mesage jumps.
GoTo dalej2
Next i
Exit Sub
dalej2:
Select Case i
Case 0
With usfOKNAR01.MultiPage1.Pages(9).lb4
.Clear
.ColumnCount = rs.Fields.Count
'NAGLOWKI
w = 0
For z = 0 To rs.Fields.Count - 1
.AddItem
.List(w, z) = rs.Fields(z).Name
Next z
w = 1
Do
.AddItem
For z = 0 To rs.Fields.Count - 1
If IsNull(rs.Fields(z)) = True Or rs.Fields(z).Value = 0 Then
.List(w, z) = "Brak danych!"
Else
.List(w, z) = rs.Fields(z).Value
End If
Next z
w = w + 1
rs.MoveNext
Loop Until rs.EOF
End With
Case 1
With usfOKNAR01.txtfakt4
.ColumnCount = rs.Fields.Count
.Clear
w = 0
rs.MoveFirst
Do
If IsNull(rs.Fields(0)) Then
.AddItem ""
Else
.AddItem
.List(w, 0) = rs.Fields(1).Value
.List(w, 1) = rs.Fields(0).Value
End If
rs.MoveNext
w = w + 1
Loop Until rs.EOF
End With
End Select
在访问我有一个名为pokaz_Raty
SQL代码查询看起来是这样的:
能somebothy看看蚂蚁帮助我与我的问题?
谢谢!
谢谢你这样做的工作! greate healp :) – MIREK