替换<a /> tag with its src attribute that have another attribute

Question

this:

$text = '<img class="fruit" src="http://exmple.com/apple.png" id="apple"><BR> 
<img class="fruit" src="http://exmple.com/Lemon.png" ><BR> 
<img src="http://exmple.com/banana.png" class="fruit"><BR>'; 

$pattern = '/<img(.*) src="([^"].*)"(.*)\>/i'; //<--the problem 
$replace = preg_replace($pattern, '$2', $text); 
echo $replace; 

give me:

http://exmple.com/apple.png" id="apple 
http://exmple.com/lemon.png 
http://exmple.com/banana.png" class="fruit 

All I need just replace them with their src value; like this:

http://exmple.com/apple.png 
http://exmple.com/lemon.png 
http://exmple.com/banana.png 

Got hours on codepad，但仍然没有所需$pattern;我之前得到了similiar question，但没有工作;我在逻辑上并不擅长，所以我需要帮助。

Answer 1

您的字符串中有一个额外的.。

// This: 
$pattern = '/<img(.*) src="([^"]*)"(.*)\>/i'; 

// Not this: 
$pattern = '/<img(.*) src="([^"].*)"(.*)\>/i'; 

然而，宁可做一个奇怪的替代删除你不想要的，我会考虑拉出你想要的部分进行打印，而不是部分。

$matches = array(); 
preg_match_all('/<img.*?src="([^"]*)"/i', $text, $matches); 
echo implode("\n", $matches[1]);