我已经尝试了所有不同类型的组合,但我只是不明白它想从我:为什么我不断收到“java.net.MalformedURLException:无协议”
java.net.MalformedURLException: no protocol: <?xml version="1.0" encoding="UTF-8" standalone="yes"?><ds><ds>...
at java.net.URL.<init>(URL.java:593)
at java.net.URL.<init>(URL.java:490)
at java.net.URL.<init>(URL.java:439)
at com.sun.org.apache.xerces.internal.impl.XMLEntityManager.setupCurrentEntity(XMLEntityManager.java:620)
at com.sun.org.apache.xerces.internal.impl.XMLVersionDetector.determineDocVersion(XMLVersionDetector.java:148)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:805)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:770)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:141)
at com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(DOMParser.java:243)
at com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.java:339)
at javax.xml.parsers.DocumentBuilder.parse(DocumentBuilder.java:177)
我已经看了其他问题,但我不知道我的XML有什么问题。
这是一个完整的XML(有一些纯文本删除):
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ds>
<ds>
<cue>ABGB : §§ 786 , 810 , 812 </cue>Die Kosten ... <cue>Anmerkung : </cue>
... <cue>Bestätigung von </cue>7
<Relation bewertung="1">Ob 56/10a </Relation>= Zak
<Relation bewertung="1">2010/773 , 440 </Relation>.
</ds>
</ds>
的生产代码:
DocumentBuilderFactory icFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder icBuilder;
Document parse = null;
try {
icBuilder = icFactory.newDocumentBuilder();
parse = icBuilder.parse(xmlString);
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
你能分享代码吗? – Mureinik
,因为您的xml **不是** [URL](https://docs.oracle.com/javase/8/docs/api/java/net/URL.html) – 2016-12-15 15:42:08
您无法创建URL对象从一个XML字符串 - 需要是一个实际的URL –