2016-05-13 115 views
3

当我运行我的docker容器时,它似乎只遵守CMD数组(python可执行文件)的第一个元素并忽略尾随参数。当入口点出现时,Docker运行命令忽略Dockerfile CMD的一部分

Dockerfile:

FROM ubuntu:14.04 

ENTRYPOINT ["/bin/bash", "-c"] 
CMD ["/virtualenv/bin/python", "/mycode/myscript.py", "--param1"] 

运行命令:

$ docker run --rm -it --volume $(pwd)/..:/mycode --volume mycontainer-virtualenv:/virtualenv mycontainer 

输出:如果我跑--detach,而不是-it

Python 3.4.3 (default, Oct 14 2015, 20:28:29) 
[GCC 4.8.4] on linux 
Type "help", "copyright", "credits" or "license" for more information. 
>>> 

同样的情况。

$ docker run --rm -it --volume $(pwd)/..:/mycode --volume mycontainer-virtualenv:/virtualenv mycontainer /virtualenv/bin/python /mycode/myscript.py --param1 
Python 3.4.3 (default, Oct 14 2015, 20:28:29) 
[GCC 4.8.4] on linux 
Type "help", "copyright", "credits" or "license" for more information. 
>>> 

如果我运行bash的容器,并从bash提示符下运行CMD,它工作正常:

如果我用CMD运行作为压倒一切的搬运工运行参数

同样也发生

$ docker run --rm -it --volume $(pwd)/..:/mycode --volume mycontainer-virtualenv:/virtualenv mycontainer bash 
[email protected]:/# /virtualenv/bin/python /mycode/myscript.py --param1 
Hello world! 

回答

3

你可能想

CMD ["/virtualenv/bin/python /mycode/myscript.py --param1"] 

,而不是

CMD ["/virtualenv/bin/python", "/mycode/myscript.py", "--param1"] 

当Dockerfile中都存在CMDENTRYPOINT时,CMD将作为默认参数进入到ENTRYPOINT中。所以你基本上是做

bash -c "/virtualenv/bin/python" "/mycode/myscript.py" "--param1" 

当你想

bash -c "/virtualenv/bin/python /mycode/myscript.py --param1" 

https://docs.docker.com/engine/reference/builder/#cmd https://docs.docker.com/engine/reference/builder/#entrypoint https://docs.docker.com/engine/reference/builder/#understand-how-cmd-and-entrypoint-interact