1
可能重复：
Why do I get “Resource id #4” when I apply print_r() to an array in PHP?
How do i “echo” a “Resource id #6” from a MySql response in PHP?
为什么我得到 “资源ID＃6” 作为在$结果？想要1或0：P
$sql = "SELECT * FROM members WHERE rchat=1 LIMIT 1";
$result = mysql_query($sql);
if (!$result) {
unlink($fn);
//$fn = $_SESSION['sess_user'].'.txt';
$fn = 'hittaingen.txt';
mysql_query("UPDATE members SET rchat=1 room='" . $_SESSION['sess_user'] . "' WHERE user='" . $_SESSION['sess_user'] . "'");
}
else {
//$fn = $result['room'].'.txt';
$fn = 'hitta.txt';
mysql_query("UPDATE members SET rchat=2 room='" . $result['room'] . "' WHERE user='" . $_SESSION['sess_user'] . "'");
}