django_rest_framwork发生“类型错误：'链接'对象不支持项目分配”

使用Django，DRF，招摇的项目。django_rest_framwork发生“类型错误：'链接'对象不支持项目分配”

网址如下配置：

schema_view = get_swagger_view(title='Pastebin API') 
urlpatterns = [ 
    url(r'^$', schema_view), 
    url(r'store', include('store.urls')), 
    ... # other urls using routers.SimplerRouter 
]

和存储/ urls.py：

router = routers.SimpleRouter() 
router.register(r'', views.StoreViewSet) 
urlpatterns = router.urls

和views.StoreViewSet：

class StoreViewSet(BaseObject, GenericViewSet): 
    permition_class =() 

    @list_route() 
    def detail(self, request): 
     return {} 

    @list_route(url_path='detail/export') 
    def detail_export(self, request): 
     return {}

后python manage.py runserver，请访问：http://127.0.0.1:8000/#和类型错误发生：

File "/usr/local/share/.virtualenvs/dev-finance/lib/python2.7/site-packages/rest_framework_swagger/views.py", line 32, in get 
schema = generator.get_schema(request=request) 
File "/usr/local/share/.virtualenvs/dev-finance/lib/python2.7/site-packages/rest_framework/schemas.py", line 242, in get_schema 
links = self.get_links(request) 
File "/usr/local/share/.virtualenvs/dev-finance/lib/python2.7/site-packages/rest_framework/schemas.py", line 276, in get_links 
insert_into(links, keys, link) 
File "/usr/local/share/.virtualenvs/dev-finance/lib/python2.7/site-packages/rest_framework/schemas.py", line 79, in insert_into 
target[keys[-1]] = value 
TypeError: 'Link' object does not support item assignment 
[ERROR] 2017-05-04 15:25:06,936 log_message(basehttp.py:131) "GET/HTTP/1.1" 500 20384

错误消息显示，Link对象不能像字典一样分配值。

如果我将方法名称从detail_export重命名为details_export，一切都很顺利。

当rest_framework的@list_route decorater 将方法的url传递给Link对象时发生猜测错误。

为什么其他方法很好？我该如何解决这个问题？

来源

2017-05-04 Dom Ran

这看起来像一个名字碰撞我。这很奇怪，因为DRF视图集中的“细节”方法被称为“检索”。它是否可以在没有大量图表生成的情况下工作 – Igonato

@Igonato视图中所有方法的名称是不同的。它的工作没有招摇。 –

正如我的想法。如果我是你的话，我只需要带上另一个名字。此外，在Python中，还有一个约定，在末尾添加“_”以打破名称冲突，例如， 'print_ =“Hello world！”;打印（print_）' – Igonato

这里是一个黑客：

打开您的环境文件夹/ lib目录/ python3.5 /站点包/ rest_framework/schemas.py
查找 “insert_into” 功能
更换这样的：
```
target[keys[-1]] = value 
```

与此：

if type(target) != coreapi.Link: 
    target[keys[-1]] = value

来源

2017-07-10 22:44:57

这是the bug in DRF。可能它会在3.6.4中修复。现在，您可以：

删除url_path从list_route：

class StoreViewSet(BaseObject, GenericViewSet): 
    permition_class =() 

    @list_route() 
    def detail(self, request): 
     return {} 

    @list_route() 
    def detail_export(self, request): 
     return {}

可以使用自定义SchemaView使用自定义SchemaGenerator：

# api/schema.py for example 

from rest_framework.permissions import AllowAny 
from rest_framework.renderers import CoreJSONRenderer 
from rest_framework.response import Response 
from rest_framework.schemas import SchemaGenerator 
from rest_framework.views import APIView 
from rest_framework_swagger import renderers 


class CustomSchemaGenerator(SchemaGenerator): 
    def get_keys(self, subpath, method, view): 
     result = super().get_keys(subpath, method, view) 
     # here you can fix your path 
     if result == ['store', 'detail', 'detail_export']: 
      return ['store', 'detail_export'] 
     return result 


class SwaggerSchemaView(APIView): 
    _ignore_model_permissions = True 
    exclude_from_schema = True 
    permission_classes = [AllowAny] 
    renderer_classes = [ 
     CoreJSONRenderer, 
     renderers.OpenAPIRenderer, 
     renderers.SwaggerUIRenderer 
    ] 

    def get(self, request): 
     generator = CustomSchemaGenerator(title='API') 
     return Response(generator.get_schema(request=request)) 

# urls.py 

from django.contrib.auth.decorators import login_required 
from api.schema import SwaggerSchemaView 

urlpatterns = [ 
    # ... 
    url(r'^swagger-url/', login_required(SwaggerSchemaView.as_view())) 
    # ... 
]

来源

2017-07-26 10:00:46

django_rest_framwork发生“类型错误：'链接'对象不支持项目分配”

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