插入多行时的虚拟结果

Question

我最近创建了一个名为Movie_Stars的表。它包含6列：Movie_Number number unique，Movie_Title varchar2（30）unique，Year_Released date not null，First_Name varchar2（15），Last_Name varchar2（15）和Movie_Category varchar2（15）。我需要插入下面的值到表：

insert all 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category) 
      values (1, 'New York Stories', 'January 1 1984', Nick, Nolte, Drama) 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)  
      values (2, 'Speed', '1999, FEB 12', Keanu, Reeves, Action) 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category) 
      values (3, 'Superman', '1982, MAR 7', Chris, Reeve, Action) 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category) 
      values (4, 'Ice Age', '2002, April 2', Chris, Rock, Cartoon) 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category) 
      values (5, 'Bowfinger', '2001, August 03', Eddie, Murphy, Comedy); 
select * from dual; 

然而，当我跑的代码，它返回的结果如下：

DUMMY 
----- 
1 x 

这是什么意思？如何解决？

Answer 1

1. 在INSERT ALL和SELECT之间有错误的分号;这意味着它们是两种不同的陈述，而不是单一的陈述。
2. 您错过了许多报价来包装您的字符串值
3. 您无法以此方式插入日期值;你必须使用一个to_date或使用ANSI标准

您可以重写代码为：

insert all 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category) 
      values (1, 'New York Stories', date '1984-01-01', 'Nick', 'Nolte', 'Drama') 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category)  
      values (2, 'Speed', date '1992-02-12', 'Keanu', 'Reeves', 'Action') 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category) 
      values (3, 'Superman', date '1982-03-07', 'Chris', 'Reeve', 'Action') 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category) 
      values (4, 'Ice Age', to_date ('02/04/2002', 'dd/mm/yyyy'), 'Chris', 'Rock', 'Cartoon') 
into movie_stars (movie_number, movie_title, year_released, first_name, last_name, movie_category) 
      values (5, 'Bowfinger', date '2001-08-03', 'Eddie', 'Murphy', 'Comedy') 
select * from dual;