2016-06-01 70 views
0
SELECT DISTINCT CONCAT('TOTAL NUMBER OF LEGS IN A TRIP NUMBER ', T1.TNUM, ' IS NOT EQUAL TO THE LARGEST NUMBER OF LEG IN THE TRIP') AS 'ERR' 
FROM TRIPLEG T1 
WHERE MAX(T1.LEGNUM) = (SELECT COUNT(T2.TNUM) 
        FROM TRIPLEG 
        WHERE T1.TNUM = T2.TNUM); 

与我的代码,我试图找到违反以下一致性约束的所有旅行。 每个行程的最后一站必须等于腿的旅行”错误111,无效使用组功能

CREATE TABLE TRIPLEG(
TNUM DECIMAL(10)  NOT NULL, 
LEGNUM DECIMAL(2) NOT NULL, 
DEPARTURE VARCHAR(30) NOT NULL,  DESTINATION VARCHAR(30) NOT NULL, 
    CONSTRAINT TRIPLEG_PKEY PRIMARY KEY (TNUM, LEGNUM), 
    CONSTRAINT TRIPLEG_UNIQUE UNIQUE(TNUM, DEPARTURE, DESTINATION), 
CONSTRAINT TRIPLEG_FKEY1 FOREIGN KEY (TNUM) REFERENCES TRIP(TNUM)); 

INSERT INTO TRIPLEG VALUES(1, 1, 'Sydney', 'Melbourne'); 
INSERT INTO TRIPLEG VALUES(1, 2, 'Melbourne', 'Hobart'); 
+0

你在where子句中使用集合函数:'MAX (T1.LEGNUM)'你不能,我会建议一个'GroupBy'和一个'Having' ... – Codexer

回答

0

尝试以下总数;)

SELECT DISTINCT CONCAT('TOTAL NUMBER OF LEGS IN A TRIP NUMBER ', T1.TNUM, ' IS NOT EQUAL TO THE LARGEST NUMBER OF LEG IN THE TRIP') AS 'ERR' 
FROM TRIPLEG T1 
GROUP BY T1.TNUM 
HAVING COUNT(T1.TNUM) <> MAX(T1.LEGNUM) 
+1

omg它的工作原理!TT谢谢你这么sooo –