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SELECT DISTINCT CONCAT('TOTAL NUMBER OF LEGS IN A TRIP NUMBER ', T1.TNUM, ' IS NOT EQUAL TO THE LARGEST NUMBER OF LEG IN THE TRIP') AS 'ERR'
FROM TRIPLEG T1
WHERE MAX(T1.LEGNUM) = (SELECT COUNT(T2.TNUM)
FROM TRIPLEG
WHERE T1.TNUM = T2.TNUM);
与我的代码,我试图找到违反以下一致性约束的所有旅行。 每个行程的最后一站必须等于腿的旅行”错误111,无效使用组功能
CREATE TABLE TRIPLEG(
TNUM DECIMAL(10) NOT NULL,
LEGNUM DECIMAL(2) NOT NULL,
DEPARTURE VARCHAR(30) NOT NULL, DESTINATION VARCHAR(30) NOT NULL,
CONSTRAINT TRIPLEG_PKEY PRIMARY KEY (TNUM, LEGNUM),
CONSTRAINT TRIPLEG_UNIQUE UNIQUE(TNUM, DEPARTURE, DESTINATION),
CONSTRAINT TRIPLEG_FKEY1 FOREIGN KEY (TNUM) REFERENCES TRIP(TNUM));
INSERT INTO TRIPLEG VALUES(1, 1, 'Sydney', 'Melbourne');
INSERT INTO TRIPLEG VALUES(1, 2, 'Melbourne', 'Hobart');
你在where子句中使用集合函数:'MAX (T1.LEGNUM)'你不能,我会建议一个'GroupBy'和一个'Having' ... – Codexer