的Servlet 3.0 HTTP 404 - 请求的资源不可用

HTTP状态404 - /WebServlet3.0/

类型状态报告

消息/WebServlet3.0/

description请求的资源不可用。

的Apache Tomcat/7.0.42

这是我ServletAsync.java文件，这是一个src下 - > com.example.servlet

import java.io.IOException; 
import javax.servlet.ServletException; 
import javax.servlet.annotation.WebServlet; 
import javax.servlet.http.HttpServlet; 
import javax.servlet.http.HttpServletRequest; 
import javax.servlet.http.HttpServletResponse; 

/** 
* Servlet implementation class ServletAsync 
*/ 

@WebServlet("/ServletAsync") 
public class ServletAsync extends HttpServlet { 
    private static final long serialVersionUID = 1L; 

    /** 
    * @see HttpServlet#HttpServlet() 
    */ 
    public ServletAsync() { 
     super(); 
     // TODO Auto-generated constructor stub 
    } 

    /** 
    * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response) 
    */ 
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 
     // TODO Auto-generated method stub 
    } 

    /** 
    * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response) 
    */ 
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 
     // TODO Auto-generated method stub 
    } 

}

这是我的web.xml文件：

<?xml version="1.0" encoding="UTF-8"?> 
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" 
    xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" 
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" 
    id="WebApp_ID" version="3.0"> 
    <display-name>WebServlet3.0</display-name> 
    <welcome-file-list> 
     <welcome-file>index.html</welcome-file> 
     <welcome-file>index.htm</welcome-file> 
     <welcome-file>index.jsp</welcome-file> 
     <welcome-file>default.html</welcome-file> 
     <welcome-file>default.htm</welcome-file> 
     <welcome-file>default.jsp</welcome-file> 
    </welcome-file-list> 

</web-app>

这是我的index.html文件：

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> 
<html> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> 
<title>Insert title here</title> 
</head> 
<body> 
    <form name="input" action="ServletAsync" method="get"> 
     Write a text : <input type="text" name="input"> <input 
      type="submit" value="Submit"> 
    </form> 
</body> 
</html>

您能否纠正我的问题。为什么我得到这个错误以及如何解决它？我只想显示网页。

来源

2013-07-23 Sanghati Mukherjee

问题得到解决。我的项目名称是webservlet3.0，当我将项目名称更改为webservlet时，我的项目已经运行。

来源

2013-07-23 13:12:56

的Servlet 3.0 HTTP 404 - 请求的资源不可用

回答

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