休眠自动递增不工作

Question

我在我的数据库中设置了Identity（1,1）的列，我无法获得hibernate注释的工作。我尝试创建新记录时遇到错误。

在我的实体中，我有以下几点。

@Entity 
@Table(schema="dbo", name="MemberSelectedOptions") 
public class MemberSelectedOption extends BampiEntity implements Serializable { 

    @Embeddable 
    public static class MSOPK implements Serializable { 
     private static final long serialVersionUID = 1L; 

     @Column(name="SourceApplication") 
     String sourceApplication; 

     @Column(name="GroupId") 
     String groupId; 

     @Column(name="MemberId") 
     String memberId; 

     @Column(name="OptionId") 
     int optionId; 

     @GeneratedValue(strategy=GenerationType.IDENTITY, generator="native") 
     @Column(name="SeqNo", unique=true, nullable=false) 
     BigDecimal seqNo; 

     //Getters and setters here... 

    } 

    private static final long serialVersionUID = 1L; 

    @EmbeddedId 
    MSOPK pk = new MSOPK(); 

    @Column(name="OptionStatusCd") 
    String optionStatusCd; 

    @Column(name="EffectiveDate") 
    Date effectiveDate; 

    @Column(name="TermDate") 
    Date termDate; 

    @Column(name="SelectionStatusDate") 
    Date selectionStatusDate; 

    @Column(name="SysLstUpdtUserId") 
    String sysLstUpdtUserId = Globals.WS_USER_ID;; 

    @Column(name="SysLstTrxDtm") 
    Date sysLstTrxDtm = new Date(); 

    @OneToMany(mappedBy="option") 
    List<MemberSelectedVariable> variables = 
          new ArrayList<MemberSelectedVariable>(); 

     //More Getters and setters here... 
} 

但是，当我尝试添加新记录时出现以下错误。

当IDENTITY_INSERT设置为OFF时，无法在表'MemberSelectedOptions'中为标识列插入显式值。我不想将IDENTIY_INSERT设置为ON，因为我想让db中的标识列管理这些值。

运行的SQL如下;在那里你可以清楚地看到插入。

insert into dbo.MemberSelectedOptions 
    (OptionStatusCd, 
    EffectiveDate, 
    TermDate, 
    SelectionStatusDate, 
    SysLstUpdtUserId, 
    SysLstTrxDtm, 
    SourceApplication, 
    GroupId, 
    MemberId, 
    OptionId, 
    SeqNo) 
values (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?) 

我在想什么？

Answer 1

可能您需要用@id标记您的字段，并且不指定generator属性。

如Hibernate Annotation - 2.2.3.1. Generating the identifier property表明，下面的例子中使用的身份发电机：

@Id @GeneratedValue(strategy=GenerationType.IDENTITY) 
public Long getId() { ... } 

Answer 2

这个组合适合我的伟大工程：

@Id 
@GeneratedValue(strategy = GenerationType.IDENTITY) 

Answer 3

当您使用@Embeddable或@EmbeddedId，主键值应该是提供由应用程序（即由非生成值组成）。您的@GeneratedValue注释被忽略。

Answer 4

不能使用复合键

Answer 5

发电机这里的例子做

@Id 
@Column(name = "col_id") 
@GeneratedValue(strategy = GenerationType.AUTO) 
private Long    colId; 

Answer 6

你不能用 做手工创建表，一切都会好的。

CREATE TABLE `Forum` (
    `name` varchar(255) NOT NULL, 
    `id` int(11) NOT NULL AUTO_INCREMENT, 
    `body` varchar(500) DEFAULT NULL, 
    PRIMARY KEY (name,`id`), 
    UNIQUE KEY `id` (`id`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin2 




import java.io.Serializable; 

import javax.persistence.Column; 
import javax.persistence.EmbeddedId; 
import javax.persistence.Entity; 

@Entity 
public class Forum implements Serializable { 

    @EmbeddedId 
    private ForumCompositePK forumPK; 
    /** 
    * 
    */ 
    private static final long serialVersionUID = 7070007885798411858L; 

    @Column(length = 500) 
    String body; 

    public String getBody() { 
     return body; 
    } 

    public void setBody(String body) { 
     this.body = body; 
    } 

    public void setForumPK(ForumCompositePK forumPK) { 
     this.forumPK = forumPK; 
    } 

    public ForumCompositePK getForumPK() { 
     return forumPK; 
    } 

} 




import java.io.Serializable; 

import javax.persistence.Column; 
import javax.persistence.Embeddable; 
import javax.persistence.GeneratedValue; 
import javax.persistence.GenerationType; 

@Embeddable 
public class ForumCompositePK implements Serializable { 

    /** 
    * 
    */ 
    private static final long serialVersionUID = 8277531190469885913L; 


    @Column(unique=true,updatable=false,insertable=false) 
    @GeneratedValue(strategy=GenerationType.IDENTITY) 
    private Integer id; 

    private String name; 

    public String getName() { 
     return name; 
    } 

    public void setName(String name) { 
     this.name = name; 
    } 

    public Integer getId() { 
     return id; 
    } 

    public void setId(Integer id) { 
     this.id = id; 
    } 



}