为什么从sqlite返回值返回一个空的数组

使用下面的代码将值添加到数据库。为什么从sqlite返回值返回一个空的数组

public void addComplianceAcceptability(ComplianceAcceptability complianceAcceptability) { 
    SQLiteDatabase sqLiteDatabase = this.getWritableDatabase(); 
    ContentValues contentValues = new ContentValues(); 

    contentValues.put(KEY_ID, complianceAcceptability.getId()); 
    contentValues.put(KEY_COUNTRY_ID, complianceAcceptability.getCountryId()); 
    contentValues.put(KEY_DOMAIN_ID, complianceAcceptability.getDomainId()); 
    contentValues.put(KEY_UNIT_ID, complianceAcceptability.getUnitId()); 
    contentValues.put(KEY_COMPLIANCE_ID, complianceAcceptability.getComplianceId()); 
    contentValues.put(KEY_COMPLIANCE_NAME, complianceAcceptability.getCompliancenName()); 
    contentValues.put(KEY_COMPLIANCE_FREQUENCY, complianceAcceptability.getComplianceFrequency()); 
    contentValues.put(KEY_COMPLIANCE_APPLICABLE, complianceAcceptability.getComplianceApplicable()); 
    contentValues.put(KEY_COMPLIANCE_OPTED, complianceAcceptability.getComplianceOpted()); 

    sqLiteDatabase.insert(TABLE_COMPLIANCE_ACCEPTABILITY, null, contentValues); 
    sqLiteDatabase.close(); 
}

入境处尝试使用以下代码来访问值，

public List<ComplianceAcceptability> getAllAcceptability() { 

     List<ComplianceAcceptability> complianceAcceptabilityList = new ArrayList<>(); 

     String selectQuery = "SELECT * FROM " + TABLE_COMPLIANCE_ACCEPTABILITY; 

     SQLiteDatabase db = this.getWritableDatabase(); 
     Cursor cursor = db.rawQuery(selectQuery, null); 

     if (cursor.moveToFirst()) { 
      do { 
       ComplianceAcceptability complianceAcceptability = new ComplianceAcceptability(); 

       complianceAcceptability.setId(Integer.parseInt(cursor.getString(0))); 
       complianceAcceptability.setCountryId(cursor.getString(1)); 
       complianceAcceptability.setDomainId(cursor.getString(2)); 
       complianceAcceptability.setUnitId(cursor.getString(3)); 
       complianceAcceptability.setComplianceId(cursor.getString(4)); 
       complianceAcceptability.setCompliancenName(cursor.getString(5)); 
       complianceAcceptability.setComplianceFrequency(cursor.getString(6)); 
       complianceAcceptability.setComplianceApplicable(cursor.getString(7)); 
       complianceAcceptability.setComplianceOpted(cursor.getString(8)); 

      } while (cursor.moveToNext()); 
     } 

     return complianceAcceptabilityList; 
    }

的问题是，它返回一个空数组。但是，当我尝试在addComplianceStatus内打印contentValues时，它当然会打印所有值的数组。

来源

2016-03-05 Hara Hara Mahadevaki

你忘了将它添加到列表中：d –

哈哈哈哈，是的！谢谢 –

你永远不会添加任何东西到complianceAcceptabilityList。您只需指定一次，然后在返回之前不做任何事情。也许你想在每次迭代时通过光标添加complianceAcceptability？

来源

2016-03-05 07:17:36

我已经将它添加到列表中，现在和现在它打印的内存地址，而不是值 –

如果您希望它打印一些东西，而不是您所看到的默认值，则需要在对象上实现toString方法现在。 –

它现在的作品。感谢你 –

在这里你是不是添加complianceAcceptability对象到complianceAcceptabilityList，修改后的代码：

if (cursor.moveToFirst()) { 
     do { 
      ComplianceAcceptability complianceAcceptability = new ComplianceAcceptability(); 

      complianceAcceptability.setId(Integer.parseInt(cursor.getString(0))); 
      complianceAcceptability.setCountryId(cursor.getString(1)); 
      complianceAcceptability.setDomainId(cursor.getString(2)); 
      complianceAcceptability.setUnitId(cursor.getString(3)); 
      complianceAcceptability.setComplianceId(cursor.getString(4)); 
      complianceAcceptability.setCompliancenName(cursor.getString(5)); 
      complianceAcceptability.setComplianceFrequency(cursor.getString(6)); 
      complianceAcceptability.setComplianceApplicable(cursor.getString(7)); 
      complianceAcceptability.setComplianceOpted(cursor.getString(8)); 
     complianceAcceptabilityList.add(complianceAcceptability);   

     } while (cursor.moveToNext()); 
    }

来源

2016-03-05 07:19:01 Awadesh

现在它打印一些内存地址而不是值 –

为什么从sqlite返回值返回一个空的数组

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