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我应该为我的char **分配足够的内存。我使用gdb并找到了分段错误的一点。我一直被困在这个部分大约一个小时,似乎无法弄清楚为什么我会违规。无法弄清楚我是如何得到seg错误
输出程序的:
尺寸:10,20
开始:1,1
端:10,20
分段故障(核心转储)
10 = m1.xsize
20 = m1.ysize
1 = m1.xstart
1 = m1.ystart
10 = m1.xend
20 = m1.yend
我的代码片段:
typedef struct mazeStruct
{
char** arr;
int xsize, ysize;
int xstart, ystart;
int xend, yend;
} maze;
/* read in the size, starting and ending positions in the maze */
fscanf (src, "%d %d", &m1.xsize, &m1.ysize);
fscanf (src, "%d %d", &m1.xstart, &m1.ystart);
fscanf (src, "%d %d", &m1.xend, &m1.yend);
/* print them out to verify the input */
printf ("size: %d, %d\n", m1.xsize, m1.ysize);
printf ("start: %d, %d\n", m1.xstart, m1.ystart);
printf ("end: %d, %d\n\n", m1.xend, m1.yend);
//allocating memory for 2d char array
m1.arr = (char**)malloc(m1.xsize+2 * sizeof(char*));
for(i = 0; i < m1.xsize+2; i++)
m1.arr[i] = (char*)malloc(m1.ysize+2);
/* initialize the maze to empty */
for (i = 0; i < m1.xsize+2; i++) <---- when i = 6 it seg faults
for (j = 0; j < m1.ysize+2; j++)
m1.arr[i][j] = '.';
我没有分配足够的内存,或者我做错了什么?
非常感谢。这是我犯的一个非常愚蠢的简单错误。非常感激。 – juice 2013-03-06 08:33:57